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R
Raj Pandey

Contributor-Level 9

I A B = m ( 0 ) 2 + 2 m a 2 2 + 3 m a 2 2

I A B = m a 2 2 + 3 m a 2 4 = 5 m a 2 4 I A B = 25 m a 2 20 = N 20 m a 2 N = 25

 

New answer posted

2 months ago

0 Follower 10 Views

R
Raj Pandey

Contributor-Level 9

Acceleration of the combined system along the incline is given by

a = g s i n ? 37 ? a = 3 g 5

With respect to block M :

N = m g - m a s i n ? 37 ? = m g - 3 m g 5 3 5 N = 16 25 m g μ N = m a c o s ? 37 ? μ 16 25 m g = 3 m g 5 4 5 μ = 3 4 = 750 1000 I = 750

 

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2 months ago

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R
Raj Pandey

Contributor-Level 9

Δ E 1 = 12400 e V ? 1085 ? = 11.43 e V

Δ E 2 = 12400 304 e V = 40.80 e V

Δ E 1 + Δ E 2 = 54.4 e V 1 n 1 2 - 1 n 2 2 52.23 = 54.4 1 n 1 2 - 1 n 2 2

If n 1 = 1 n 2 = 5

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

1 20 = ( 1.55 - 1 ) 1 R 1 - 1 R 2

1 f = ( 1.50 - 1 ) 1 R 1 - 1 R 2

Divide (1) by (2), f 20 = 0.55 0.50

f = 22 c m

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

τ ? = d L ? d t = A ? * L ? d L ? d t L ?

Statement (1) is correct

 

The component of L ?  in the direction of A ?  is always perpendicular to  , so it does not change.

 Statement (2) is correct

The magnitude of L ?  does not change with time as τ ? L ?  .

 Statement (3) is correct

The direction of  L ? changes with time.

Statement (4) is incorrect.

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

(I? /2)cos²θ = (18/100)I?
⇒ cos²θ = 9/25
⇒ cosθ = 3/5 ⇒ θ = 53°

New answer posted

2 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

    Potential difference across R?
(R? / (R? +R? ) * V is greater than zenor voltage
⇒ i? = V_z/R? = 20/1000 A = 20 mA
Current through R? , i? = (40-V_z)/R? = 20/500 = 40 mA


Current through zener diode = i? - i? = 20 mA

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

I? = P? – P? = 3 * 4? – 3 * 3î = 12? – 9î |I? | = √12² + 9² = 15kgm/s

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

at t = 0, I = 0; E = L (dI/dt) ⇒ dI/dt = E/L = 1.5/0.1 = 15 A/s

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