Physics

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New answer posted

9 months ago

0 Follower 248 Views

V
Vishal Baghel

Contributor-Level 10

W D = Δ Q V

Δ Q = 4 μ C

Q i = 2 * 4 2 + 4 * 6 = 8 μ C

Q f = 1 2 μ C = C e q * 6

C e q = 2 μ F C 1 = C 2 = 4 μ F

k = C 1 C 0 = 2

New answer posted

9 months ago

0 Follower 61 Views

V
Vishal Baghel

Contributor-Level 10

i = v R + G

i 2 = v S G S + G + R * S S + G

2 S S G + R G + R S = 1 R + G

S R R S = G

R > > S

G S

New answer posted

9 months ago

0 Follower 35 Views

V
Vishal Baghel

Contributor-Level 10

v = 2 9 r 2 g ( ρ σ ) η

v ' = 2 9 r 2 g ( ρ 2 σ ) η

New answer posted

9 months ago

0 Follower 177 Views

V
Vishal Baghel

Contributor-Level 10

Field lines are proportional to quantity of charge & they originate at positive charge & terminates at -ve charge or at  

New answer posted

9 months ago

0 Follower 91 Views

V
Vishal Baghel

Contributor-Level 10

B = m g B 1 = B 2

ρ 1 V 1 g = B = ρ w v L D g

ρ 2 ρ W = f 2

ρ 1 > ρ 1

New answer posted

9 months ago

0 Follower 29 Views

V
Vishal Baghel

Contributor-Level 10

v = 1 0 8 * 5 1 8 = 3 0 m / s

f 1 = C C v f 0

f = 3 3 0 3 3 0 + 3 0 * 5 0 0 = 3 3 3 6 * 5 0 0 = 5 5 0 0 1 2

New answer posted

9 months ago

0 Follower 59 Views

V
Vishal Baghel

Contributor-Level 10

λ = v 2 π d 2 n N a = R T 2 π d 2 p N a

= 2 5 3 * 3 0 0 2 * π * 1 0 2 0 * 1 0 5 * 6 * 1 0 2 3

x 3 = v n N a

= ( 2 5 3 * 3 0 0 1 0 5 * 6 * 1 0 2 3 ) 1 / 3

New answer posted

9 months ago

0 Follower 157 Views

V
Vishal Baghel

Contributor-Level 10

d H d t = 2 π x 2 k d T d x

d H d t = 2 π * k * 4 5 1 2 . 5 1 3 = 2 . 2 5 π k W

New answer posted

9 months ago

0 Follower 30 Views

V
Vishal Baghel

Contributor-Level 10

T = 2 π l g

In summer, length will increase due to expansion, hence for same time period we have to decrease l  in summer.

New answer posted

9 months ago

0 Follower 347 Views

V
Vishal Baghel

Contributor-Level 10

I = m 4 * a 2 3 * 2 + m 4 * ( a 2 1 2 + ( a 2 ) 2 + a 2 ) * 2

= m a 2 6 + 2 3 m a 2 = m a 2 + 4 m a 2 6 = 5 m a 2 6

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