Physics Thermal Properties of Matter

Get insights from 57 questions on Physics Thermal Properties of Matter, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics Thermal Properties of Matter

Follow Ask Question
57

Questions

0

Discussions

4

Active Users

6

Followers

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

According to question, we can write

d = d 0 ( 1 + α Δ T ) 6 . 2 4 1 = 6 . 2 3 0 ( 1 + 1 . 4 * 1 0 5 * Δ T )

T = 1 2 6 . 1 8 + 2 7 = 1 5 3 . 1 8 ° C  

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

According to question, we can write

d = d 0 ( 1 + α Δ T ) 6 . 2 4 1 = 6 . 2 3 0 ( 1 + 1 . 4 * 1 0 5 * Δ T )

T = 1 2 6 . 1 8 + 2 7 = 1 5 3 . 1 8 ° C

New answer posted

2 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

When Two rods are connected in series

Q=A (T1T2)td1K1+d2K1=A (T1T2)t (d1+d2)/K

d 1 + d 2 K = d 1 K 1 + d 2 K 2

K= (d1+d2)d1K1+d2K1

New answer posted

2 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

400 * 1 * 12.5 = 500 * 5 * (100 – 36.5)

S = 1 0 6 3 . 5 c a l / g m ° C        

1 g m = 1 6 3 . 5 m o l  

S = 10 cal/mol °C

New answer posted

2 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

d H d t = 2 π x 2 k d T d x

d H d t = 2 π * k * 4 5 1 2 . 5 1 3 = 2 . 2 5 π k W

New answer posted

2 months ago

0 Follower 1 View

S
Syed Aquib Ur Rahman

Contributor-Level 10

It's the energy that is needed for a change of state to transition from one substance or physical state to another. Remember that the main condition for latent heat is that there is no temperature change when the energy is absorbed or released. 

New answer posted

2 months ago

0 Follower 1 View

S
Syed Aquib Ur Rahman

Contributor-Level 10

You will be seeing these temperature plateaus appearing on the heating curve at the main melting and boiling points. The reason for that is the energy reaches latent heat. And we know that latent heat is the energy that lets phase transitions occur without increasing the temperature. 

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

r = r? (1 + αΔT) ⇒ r – r? = r? αΔT
⇒ 3 * 10? ³ = 1 * 1.2 * 10? ΔT ⇒ ΔT = 250°C

New answer posted

2 months ago

0 Follower 32 Views

A
alok kumar singh

Contributor-Level 10

 

θ = 3 0 °

A B = R s i n θ = 2 R

New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

(K (4A)/l) (100 – θ) = (KA/l) (θ – 50)
⇒ 400 – 4θ = θ – 50 ⇒ 5θ = 450 ⇒ θ = 90°C

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.