Science

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9 years ago

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Vikash Ranjan

Guide-Level 15

There are no branch in engineering which leaves maths subject as all branches' syllabus carry the math subject, and there are many colleges for that like top colleges that offer bio-technology courses are the IITs (Kanpur, Roorkee and Guwahati); NIT Warnagal; NSIT Delhi; Thapar University; Manipal Institute of Technology, Karnataka; Vellore Institute of Technology (VIT); and Sir M. Visvesvaraya Institute of Technology.

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9 years ago

0 Follower 333 Views

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Ritesh BhandariA figment of nothing.

Contributor-Level 8

You need to score above 60% marks.

New answer posted

9 years ago

0 Follower 103 Views

S
subhasish debroy

Guide-Level 13

Hi,
In a separate post from you yesterday, I tried to substantiate your query. You can go through.

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9 years ago

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Sunil SoniManagement & IT Consultant

Scholar-Level 18

IITian can become a scientist in India and abroad easily. You can join IIT after completing class 12th through JEE Mains and JEE Advance. You can join IIT for M.Tech through GATE examination. You can join IIT after B.Sc by appearing in JAM examination.

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9 years ago

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Chetna S

Scholar-Level 17

Hi,
If you are looking for a year Diploma, you can go for any computer course or anything that might help you once you join CDS.

New answer posted

9 years ago

0 Follower 2.8k Views

N
Nitish Bhat

Beginner-Level 2

Prove that:
tan13A-tan9A tan4A=tan13A tan9A tan4A
For this equation, we will use the formula:
I) tan 2a= tan(a + a) and,
II) tan (a + b)= (tan a+ tan b)/(1-tan a tan b)
From (I), we can say
tan 13A= tan (9A+4A)
but, tan(9A+4A)=(tan 9A + tan 4A)/ (1-tan 9Atan 4A)
Therefore tan13A=(tan 9A+tan4A)/(1-tan9Atan4A)
=tan13A-tan13Atan9Atan4A=tan 9A+tan 4A
Therefore,
tan13A-tan9A-tan4A=tan13A tan9A tan4A

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