Sets

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New answer posted•a year ago
P
a year ago

47. Let C and T be the set of people who likes cricket and tennis respectively. Then,

n (C) = 40, people who likes cricket

n (C ∪T) = 65, people who likes either cricket or tennis

and n (C ∩T) = 10, people who likes both

So, n (C ∪T) = n (C) + n (T) n (C ∩T)

65 = 40 + n (T) 10

n (T)

...Read more

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New answer posted•a year ago
P
a year ago

46. Let A and B but the set of people who likes coffee and tea.

Then, n (A) = 37. no. of people who like coffee

n (B) = 52, no. of people who like tea.

As each person likes at least one of the two drink,

n (A ∪B) = 70.

So using, n (A ∪B) = n (A) + n (B) n (A ∩B)

n (A ∩B) = n (A) + n

...Read more

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New answer posted•a year ago
P
a year ago

45. Given, n (X) = 40

n (Y ∪Y) = 60.

n (X ∩Y) = 10.

n (Y) =?

Using, n (X ∪Y) = n (X) + n (Y) n (X ∩Y)

60 = 40 + n (y) 10.

n (Y) = 60 - 40 + 10

n (Y) = 30.

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New answer posted•a year ago
P
a year ago

44. Given, n (S) = 21

n (T) = 32

n (S ∩T) = 11.

Using, n (S ∪T) = n (S) + n (T) n (S ∩T)

= 21 + 32 11

= 42.

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New answer posted•a year ago
P
a year ago

43. Let H and E be set if people who speak Hindi and English respectively. there,

n (H) = 250, people speak Hindi n (E) = 200, people speak English

n (H ∪E) = 400, people speaks either Hindi or English

So, n (H ∩E) = n (H) + n (E) n (H ∩E)

= 250 + 200 400

= 50

So, 50 people can speak bo

...Read more

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New answer posted•a year ago
P
a year ago

42. Given, n (X ∪Y) = 18.

n (X) = 8.n (Y) = 15.n (X ∩Y) =?

Using n (X ∩Y) = n (X) + n (Y) n (X ∪Y)

= 8 + 15 18.

= 5.

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New answer posted•a year ago
P
a year ago

41. Given, n (X)= 17

n (Y) = 23

n (X ∪Y)= 38.

So, n (X ∪ Y) = n (X) + n (Y) n (X ∩Y)

n (X ∩Y) = n (X) + n (Y) n (X ∪Y)

= 17 + 23 38.

= 2

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New answer posted•a year ago
P
a year ago

40.  (i) A ∪A' = U

(ii) ? ∩ A = U ∩ A = A.

(iii) A ∩ A' = ?  .

(iv) U' ∩ A = ?  ∩ A = ?  .

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New answer posted•a year ago
P
a year ago

39. A' = U – A

= Set of all triangle in a plane - Set of all triangle with at least the angle different from 60°.

= Set of all triangle with each angle 60°.

A? = set of all equilateral triangle.

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New answer posted•a year ago
P
a year ago

38. (i) (A∪ B)' = U – (A ∪B)

(ii) A' ∩ B' = (AU B)' = U – (AU B)

(iii) (A ∩ B)' = U – (A ∩ B)
(iv) A' U B' = (A ∩ B)' = U – (A ∩ B)'.

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