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New answer posted
4 months agoContributor-Level 10
28. A = {1,2,3,4,5, 6, …}
B = {2,4,6, …}
C = {1,3,5, …}
D = {2,3,5, …, }
(i) A ∩ B = {1,2,3,4 …} ∩ {2,4,6, …} = {2,4,6 …} = B.
(ii) A ∩ C = {1,2,3,4, …} ∩ {1,3,5 …} = {1,3,5, …} = C.
(iii) B ∩ C = {2,4,6, …} ∩ {1,3,5, …} = .
(iv) B ∩ D = {2,4,6 …} ∩ {2,3,5 …} = {2}
(v) C ∩ D = {1,3,5, …} ∩ {2,3,5 …} = {3,5,7 …} = {x : x is odd prime number}
New answer posted
4 months agoContributor-Level 10
27. (i) A ∩ B = {3,5,7,9,11} ∩ {7,9,11,13}
= {7, 9, 11}
(ii) B ∩ C = {7,9,11,13} ∩ {11,13,15}
= {11,13}
(iii) A ∩ C ∩ D = (A ∩ C) ∩ D
= [ {3,5,7,9,11} ∩ {11,13,15}] ∩ {15,17}.
= {11} ∩ {15,17} = .
(iv) A ∩ C = {3,5,7,9,11} ∩ {11,13,15}.
= {11}
(v) B ∩ D = {7,9,11,13} ∩ {15,17}=
(vi) A ∩ (B∪ C) = {3,5,7,9,11} ∩ [ {7,9,11,13}∪ {11,13,15}]
= {3,5,7,9,11} ∩ {7,9,11,13,15}.
= {7,9,11}
(vii) A ∩ D = {3,5,7,9,11} ∩ {15,17} = .
(viii) A ∩ (B ∪ D) = {3,5,7,9,11} ∩ [ {7,9,11,13} ∪ {15,17}]
= {3,5,7,9,11} ∩ {7,9,11,13,15,17}
= {7,9,11}
(ix) (A ∩ B) ∩ (B ∪ C) = [ {3
New answer posted
4 months agoContributor-Level 10
26. (i) X ∩ Y = {1,3,5} ∩ {1,2,3} = {1,3}
(ii) A = {a, e, i, o, u} ∩ {a, b, c} = {a}
(iii) A ∩ B = {3,6,9,12 …} ∩ {1,2,3,4,5}
= {3}
(iv) A ∩ B = {2,3,4,5,6} ∩ {7,8,9} =
(v) A ∩ B = {1,2,3} ∩ =
New answer posted
4 months agoContributor-Level 10
25. (i) A B = {1, 2, 3, 4} {3, 4, 5, 6}
= {1, 2, 3, 4, 5, 6}
(ii) A C = {1, 2, 3, 4} {5, 6, 7, 8}
= {1, 2, 3, 4, 5, 6, 7, 8}
(iii) B C = {3, 4, 5, 6} {5, 6, 7, 8}
= {3, 4, 5, 6, 7, 8}
(iv) B D = {3, 4, 5, 6} {7, 8, 9, 10}
= {3, 4, 5, 6, 7, 8, 9, 10}
(v) A B C = (A B) C = {1,2,3,4,5,6} {5,6,7,8}
= {1, 2, 3, 4, 5, 6, 7, 8}
(vi) A B D = (A B) D = {1,2,3,4,5,6} {7,8,9,10}
= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
(vii) B C D = (B C) D = {3,4,5,6,7,8} {7,8,9,10}
= {3, 4, 5, 6, 7, 8, 9, 10}
New answer posted
4 months agoContributor-Level 10
24.If A? B then let a A and also a B.
but b B and b A i.e, A = {a} and B = {a, b}
So, A B = {x : x A or x B}
= {a, b}
= B
New answer posted
4 months agoContributor-Level 10
23. Given, A = {a, b}
B = {a, b, c}
Yes A B as a, b A and a, b B.
And A B = {a, b} {a, b, c} = {a, b, c} = B
New answer posted
4 months agoContributor-Level 10
22. (i) X∪ Y = {1,3,5}∪ {1,2,3} = {1,2,3,5}.
(ii) A ∪B = {a, e, i, o, u} ∪ {a, b, c} = {a, b, c, e, i, o, u}
(iii) A = {3, 6, 9, 12 …}
B = {1, 2, 3, 4, 5}
So, A∪ B = {3, 6, 9, 12, …}∪ {1, 2, 3, 4, 5}
= {1, 2, 3, 4, 5, 6, 9, 12 …}
(iv) A = {2, 3, 4, 5, 6}
B = {7, 8, 9}
So, A∪ B = {2, 3, 4, 5, 6}∪ {7, 8, 9} = {2, 3, 4, 5, 6, 7, 8, 9}
(v) A ∪B = {1, 2, 3} ∪ = {1, 2, 3}.
New answer posted
4 months agoContributor-Level 10
21. Universal set of A, B and C must includes all elements of A, B and C, i.e. 0,1,2,3,4,5,6,8.
So, the universal set of A, B and C is (iii) {0,1,2,3,4,5,6,7,8,9,10}.
New answer posted
4 months agoContributor-Level 10
20. (i) The set of all triangles. U= {x : x is a triangle in a plane}
(ii) The set of all triangles. U= {x : x is a triangle in a plane}
New answer posted
4 months agoContributor-Level 10
19. (i) [–3, 0] = {x : x such that x R, –3 < x <0}
(ii) [6, 12] = {x : x R, 6 ≤ x ≤ 12}
(iii) (6, 12] = {x : x R, 6 < x 12}
(iv) [–23, 5) = {x : x R, –23 ≤ x < 5}
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