Sets

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New answer posted•a year ago

17. How many elements has P(A), if A = ? ?

5 Views|Posted a year ago
Asked by Payal Gupta
P
a year ago

17. As A= ? , no elements

n(A) = 0 = m

So, n[P(A)] = 2m = 20 = 1.

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New answer posted•a year ago
P
a year ago

16 (i) Subset of {a} = {a}, ? .

(ii) Subset of {a, b} = ? ,{a},{b},{a, b}

(iii) Subset of {1,2,3} = ? ,{1},{2},{3}, {1,2}, {1,3}, {2,3}, {1,2,3}.

(iv) Subset of ? = ? .

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New answer posted•a year ago
P
a year ago

15. (i) False as 3 ∉ A and 4 ∉ 4. So, {3, 4} ⊂ A.

(ii) True as {3, 4} ∈ A. i.e, {3, 4} is an element of A.

(iii) True as {3, 4} ∈ A so, {3, 4} ⊂ A.

(iv) True as 1 is an element of A.

(v) False as 1 is not a set so it cannot be a subset of A.

(vi) True as 1 ∈ A,

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New answer posted•a year ago
P
a year ago

14. (i) False as every element of set {a, b} is also an element of {b, c, a} hence {a, b } ⊂  { b, c, a }.

(ii) True as every element in {a, e} is also a vowel in English alphabet.

(iii) False as 2 ∈  {1, 2, 3} but 2 ∉  {1, 3, 5}.

(iv) True as a ∈  {a} is also a ∈ 

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
P
a year ago

11. (i) A = {2, 3)

B = {x : x is solution of x2 + 5x + 6 = 0}

So, x2 + 5x + 6 = 0

x2 + 2x + 3x + 6 = 0

x (x+2) + 3 (x+2) = 0

(x+2) (x+3) = 0

x = –2, –3

So, B = {–2, –3}

So, A ≠ B.

(ii) A = {x : x is a letter in word FOLLOW}

A = {F, O, L, W}

(iii) B = {x : x is a letter in word WOLF}

B = {W, O, L, F}

So, A =

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New answer posted•a year ago
P
a year ago

10. (i) As A and B has a, b, c and d as elements and are exactly the same, Hence, A = B.

(ii) Hence, 12 ∈ A but 12 ∉ B

Similarly 18 ∈ B but 18 ∉ A.

So, A ≠ B.

(iii) A = {2,4,6,8,10} and B = {2,4,6,8,10}

So, A=B.

(iv) A= {10,20,30,40, …} and B= {10,15,20,25,30, …}

So, A ≠

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New answer posted•a year ago
P
a year ago

9. (i) We can draw infinite number of lines parallel to x-axis.

∴ The set is infinite.

(ii) There are 26 letters in the English alphabet.

∴ The set is finite.

(iii) There are infinite number which are a multiple of 5.

∴ The set is infinite

(iv) The numbers of animals living on earth are finite.

∴ The set i

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New answer posted•a year ago
P
a year ago

8. (i) The set of months of a year has 12 elements. Here, the set is finite.

(ii) The given set has the natural number as its elements. Hence, the set is infinite.

(iii) The given set has 100 elements i.e., from 1 to 100. Hence, the set is finite.

(iv) There are infinite numbers of positive integer

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