Standard Deviation

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New answer posted•a year ago
R
a year ago

Variance of a, b, c & a+2, b+2, c+2, are same.
Given: b = a + c (i)
d² = (1/3) (a² + b² + c²) - [ (a+b+c)/3]²
as a + c = b
d² = (1/3) (a² + b² + c²) - (2b/3)²
9d² = 3 (a² + b² + c²) - 4b²
⇒ b² = 3 (a² + c²) - 9d²

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New answer posted•a year ago
R
a year ago

If each observation is multiplied with p and then q is subtracted
New mean x? = px? - q ⇒ 10 = p(20)-q
and new standard deviations σ? = |p|σ? ⇒ 1 = |p|(2) ⇒ |p|=1/2 ⇒ p=±1/2
If p=1/2, then q=0. If p=-1/2, q=-20.

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New answer posted•a year ago
P
a year ago

x¯=∑i=110xi10=15∑i=110xi210− (x¯)2=15

⇒Σxi=150Σxi2=2400

Actual mean x¯=Σxi+15−2510=14010=14

Actual variance = Σxi2+152−25210− (14)2

=2400−40010−196

σ2=4σ=2

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