Thermodynamics

The correct graph between loge^R and loge(θ– θ₀) during cooling of a body may be (R is the rate of cooling and q0 is surrounding temperature)

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2 weeks ago

Heat required to raise the temperature of 5.4 g of aluminum from $35^{0} C$ to $65^{0} C$ is (Molar heat capacity of $A I = 24 J m o l^{- 1} K^{- 1}$ )

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Moles of $A I = \frac{5.4}{27} = \frac{1}{5}$ $\frac{}{} \frac{}{}$

$q = n C ? T = \frac{1}{5} * 24 * 30 = 144 J$

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If equilibrium constant $K_{c}$ for a reaction is $10^{10}$ at $27^{0} C$ , then $? G^{0}$ of the reaction at $27^{0} C$ will be

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$? G^{0} = - 2.303 R T \log ? K$

$= - 2.303 * R * 300 * \log ? 10^{10}$

$= - 2.303 * 3000 R$

=-6909 R

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For the reaction, $2 C l (g) - ? C l_{2} (g)$ , the sign of $? H$ and $? S$ respectively are

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$2 C l (g) \to C l_{2} (g)$ is exothermic process so $? H < 0$

$? n_{g} < 0 s o, ? S < 0$

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2 weeks ago

A cannot engine works as a refrigerator between $250 K$ and $300 K$ . It receives $500 c a l$ heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is nearly

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$C O P = \frac{Q_{t}}{W} = \frac{T_{l o w}}{T_{h i g h} - T_{l o w}} = \frac{250}{300 - 250} = 5$

$\frac{Q_{L}}{W} = 5$

$W = \frac{500 * 4.2}{5} 420 J$

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2 weeks ago

Which of the following is correct for a reaction to be spontaneous?

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$Δ G = Δ H - T Δ S$

For spontaneity

$\begin{array}{l} Δ G = - v e \\ Δ S = + v e \\ Δ H = - v e \end{array}$

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Kindly go throught the questions

Entropy is a

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· $Δ S$ is a state function because its value depends only on the state of the system and not on how it is reached.

· Entropy is an extensive property because its value depends on the quantity of matter present in the system.

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2 weeks ago

The total kinetic energy associated with n moles of monoatomic gas is

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Total kinetic energy associated with 'n' moles of monoatomic gas is = $\frac{3}{2} n R T$

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3 weeks ago

The volume V of a given mass of monoatomic gas changes with temperature T according to the relation $V = k T^{\frac{2}{3}} .$ The work done when temperature changes by 90 K will be xR. The value of x is…….

[R = universal gas constant]

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$V = k T^{\frac{2}{3}}$

-> $T V^{- \frac{3}{2}} = K$

$\Rightarrow γ - 1 = - 3 / 2$

$\Rightarrow γ = - 1 / 2$

Work done = $\frac{n R Δ T}{- y + 1} = \frac{1 * R * 90}{3 / 2} = 6 R$

->n = 60

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3 weeks ago

The internal energy (U), pressure (P) and volume (V) of an ideal gas are related as U = 3PV + 4. The gas is:

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