Aldehydes, Ketones and Carboxylic Acids

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Benzal chloride can be made by chlorinating toluene in the presence of sunshine and then using the hydrolysis process to obtain benzaldehyde. This method can be used to make benzaldehyde in a commercial setting.

 

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alok kumar singh

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Ans:

A: Ethane-1, 2-dial

B: Benzene-1, 4-carbaldehyde

C: 3-Bromobenzaldehyde

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

 

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

(i) 3-Phenylprop-2-ene-1-al.

(ii) Cyclohexanecarbaldehyde

(iii) 3-Oxopentan-1-al

(iv) IUPAC name: But-2-enal

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alok kumar singh

Contributor-Level 10

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Ketone group should have methyl ketone in the iodoform test. Yellow PPT is formed when the ketone, base, and iodine react. If it's methyl ketone, the test will come back positive. Pentan-2-one and pentan-3-one are the methyl ketones.

 

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alok kumar singh

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Butanol is a four-carbon aldehyde, with the aldehyde group on the fourth carbon. It has a functional group and a carbonyl group that interacts dipole-dipole. Because butanol possesses a polar O-H bond, it exhibits intermolecular H bonding, which is not feasible in butanal due to the lack of a polar bond. The boiling point of butanol is higher than that of butan-1-ol.

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alok kumar singh

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Ans: Liquid 'A' reduces ammoniacal silver nitrate and 'B' is a ketone which forms white crystalline solid on treatment with hydrogen sulphite

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alok kumar singh

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Ans: Functional isomers

Compound I will react faster with HCN due to less steric hindrance and greater positive charge on carbon atom of carbonyl group. Two methyl groups increase electron density on carbonyl carbon in compounds II hence the rate of nucleophilic attack is less.
Mechanism of the reaction:

 

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alok kumar singh

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Ans: The aromatic compound 'A' does not give Tollen's reagent test, it is not an aromatic aldehyde. As it responds to an iodoform test called methyl ketone.

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alok kumar singh

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans:

Fehling's test is positive when compound 'B' is used. It gives an iodoform test and proves that it is an aldehyde. Because it fails Fehling's test, compound 'C' is a ketone.

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