B.Tech Eligibility
Get insights from 2.4k questions on B.Tech Eligibility, answered by students, alumni, and experts. You may also ask and answer any question you like about B.Tech Eligibility
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
a year agoContributor-Level 8
To join B.E./B.Tech at SRIT, candidates must pass 10+2 with Physics, Chemistry, and Mathematics, scoring at least 45% (General) or 40% (reserved). Admission is through Tamil Nadu Engineering Admissions (TNEA) counselling by Anna University. Direct admission is usually not available.
New answer posted
a year ago
Contributor-Level 10
To be eligible for the B.E./B.Tech programme at Kalyani Charitable Trust's Late G.N. Sapkal College of Engineering, Nashik, candidates must have completed 10+2 with Physics and Mathematics as compulsory subjects, along with one of Chemistry, Biology, Technical Vocational Subject, Computer Science, Information Technology, Informatics Practices, Agriculture, Engineering Graphics, or Business Studies, securing at least 45% marks (40% for reserved categories). They must have a non-zero score in either MHT-CET or JEE Main (Paper I) and should be Indian nationals. For Direct Second Year (Lateral Entry), candidates should have passed a releva
New question posted
a year agoNew question posted
a year agoNew question posted
a year agoNew question posted
a year agoNew question posted
a year agoNew question posted
a year agoNew answer posted
a year agoContributor-Level 8
To be eligible for admission to the BE/BTech course at Einstein College of Engineering, the candidate has to score a minimum of 45% aggregate in class 12 in a relevant stream from any recognised board. Eligible students will have to appear for the TNEA counseling and score valid marks to be eligible for the course.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 708k Reviews
- 1850k Answers
