Biomolecules
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14.3 How do you explain the absence of aldehyde group in the pentaacetate of D-glucose?
14.3 How do you explain the absence of aldehyde group in the pentaacetate of D-glucose?
14.3
D-glucose reacts with hydroxylamine (NH2OH) to form oxime due to the presence of the aldehyde functional group (-CHO). This is due to the cyclic structure of glucose which forms an open chain structure in an aqueous medium, which then reacts to give an oxime.

But in case of pentaacetate of
14.2 What are the expected products of hydrolysis of lactose?
14.2 What are the expected products of hydrolysis of lactose?
14.2
Lactose is a disaccharide carbohydrate (made up of two monosaccharide units) composed of β-D-galactose and β-D-glucose units. Hydrolysis breaks the glycosidic bond converting sucrose into β-D- galactose and β-D-glucose.
NOTE: But however, this reaction is so slow that it takes years for the solut
14.1 Glucose or sucrose is soluble in water but cyclohexane or benzene (simple six membered ring compounds) is insoluble in water. Explain.
14.1 Glucose or sucrose is soluble in water but cyclohexane or benzene (simple six membered ring compounds) is insoluble in water. Explain.
14.1
Glucose and sucrose are carbohydrates (optically active polyhydroxy aldehydes or ketones).
Structure of glucose:

Structure of sucrose:

As you can see both the compounds have five –OH and eight –OH groups respectively. These –OH groups are responsible for the extensive hydrogen bonding w