CBSE 12th

It's not easy to calculate your TNEA (Tamil Nadu Engineering Admissions) rank based just on your 12th CBSE scores (160), as TNEA ranks are established by a normalisation method that takes into account all candidates' performance in addition to your 12th marks. The precise ranking is determined by the total number of candidates, their grades, and the authorities' normalisation algorithm, which varies annually. A CBSE score of 160 is typically regarded as normal to above average. You would need to be aware of the whole score distribution and the normalisation process for the TNEA exam given in that specific year in order to obtain a more precise estimate.

Yes, you are eligible to get admission to the BCom at Trinity Institute of Technology and Research with 50% in your Class 12. The basic eligibility criteria for admission to the BCom course require candidates should have passed Class 12 from a recognised board of education. Additionally, candidates must have studied Commerce subjects, including Accountancy, Finance, Economics, with at least an aggregate of 50%. However, admission to this course is entirely merit-based, so candidates should ensure they have a strong academic performance in their higher secondary education. While candidates can be eligible with 50%, the merit cut-off may vary each year.

According to the LD College of Engineering's qualifying criteria for candidates to appear for the GUJCET Exam, students must have a minimum of 45% in class 12th if they belong to an unreserved category. However, candidates from the reserved category must have a grade point average of 40% in class 12. Candidates applying for GUJCET must review the entire GUJCET eligibility criteria before filling out the application form.

Candidates who do not meet the GUJCET eligibility standards will not be considered for admission as per the norms given by Gujarat Secondary and Higher Secondary Education Board (GSEB).

The various conditions of eligibility for GUJCET 2024 as per Gujarat Secondary and Higher Secondary Education Board are 

·       The candidate must be an Indian and should have a Gujarat domicile.

·       The candidates should have passed or appeared for Class 12 or equivalent.

·       The candidate must have studied Physics, Chemistry, Mathematics/ Physics, Chemistry, and Biology as the main subject for pharmacy.

·       The candidate must have studied Physics, Chemistry, and Mathematics as the main subject for Engineering.

·       Candidates should have scored 45% (40% for the reserved category) in Class 12.

The minimum eligibility criteria for admission to B.Tech courses are -

• 45% or more in 10+2

• A Valid score in any one of the two entrance exams i.e JEE Main, MHT CET

As per the VJTI Mumbai MHT CET cutoff 2023, the Round 1 and the Last Round closing scores for B.Tech are given below :

The Last Round closing score for BTech ranged between 99.9 and 95.51, among which B.Tech. in Computer Engineering was the most competitive specialisation, and the second most competitive specialisation was B.Tech. in Information Technology.

Talking about the previous years' cutoff, VJTI Mumbai MHT CET cutoff 2023 for B.Tech. in Computer Engineering closed at 99.9, while in 2022, it closed at 99.82 and 99.9 in 2021.