Chemical Bonding and Molecular Structure
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New answer posted
2 months agoNew answer posted
2 months agoBeginner-Level 5
The central atom of nitrogen has 5 valence electrons as per the electronic configuraion. During the formation of , 3 valence electrons forms three sigma bonds with hydrogen and one lone electron pair is left.
- The steric number of the ammonia molecule: SN=3 bonds +1 lone pair total electron domains.
- As per the steric number, there is hybridisation in ammonia.
- The lone pair causes repulsion, which leads to a trigonal pyramidal geometry with bond angles of .
New answer posted
2 months agoBeginner-Level 5
The stability of the bond depends on various bond parameters including the bond length and bond energy. In general the shorter the bond, the lesser the bond energy will be, this leads to the stable molecule.
Since the bond order and energy of hydrogen molecule is lesser than the oxygen molecule, it is be more stable.
Molecule | Bond Order | Bond Length (pm) | Bond Energy (kJ/mol) |
---|---|---|---|
1 | 74 | 436 | |
2 | 121 | 498 |
New answer posted
2 months agoBeginner-Level 5
You can check the below given table for the comarative differences between valence bond theory and molecular orbital theory.
Feature | Valence Bond Theory (VBT) | Molecular Orbital Theory (MOT) |
---|---|---|
Basic Concept | Overlap of atomic orbitals. | Atomic orbitals combine to form molecular orbitals |
Bond Formation | Due to head-on (? ) or sideways (? ) overlap of atomic orbitals. | Linear combination of atomic orbitals (LCAO) to form bonding and antibonding MOs. |
Explanation of Magnetic Behavior | Often fails to explain magnetism of molecules (e.g., O? is paramagnetic). | Accurately explains paramagnetism/diamagnetism (O? is paramagnetic due to unpaired electrons in antibonding orbitals). |
Bond Order | Not clearly defined. | Bond order = ½ (No. of bonding electrons - No. of antibonding electrons) |
Electron Delocalization | Electrons are localized between two atoms. | Electrons may be delocalized over multiple atoms. |
Energy Consideration | Considers only overlapping orbitals and their energy. | Considers combination and energy differences of atomic orbitals. |
Applicability | Works well for simple molecules like H? , HF, etc. | Better for explaining molecules like O? , N? , and ions like NO? , CN? |
New answer posted
2 months agoBeginner-Level 5
The reason why bond angle is larger in than are given below.
- In , there is one lone pair on the nitrogen atom increases repulsion, while the lone pair on phosphorus is in a higher energy orbital and causes less repulsion.
- Nitrogen is a small and electronegative atom whereas phosphorus is larger and less electronegative than nitrogen.
- In , the bonding orbitals are nearly pure p-orbitals, which are less directionals–p hybridization, on the other hand, the bond pairs remain fairly directed, leading to a larger bond angle.
Hence, the bond angle in is about 107° ( less than the ideal tetrahedral 109.5°) due to lone pair pres
New answer posted
2 months agoBeginner-Level 5
The NO (Nitric Oxide) has 11 valence electrons while the NO? (Nitrosonium ion) has 10 valence electrons due to removal of one antibonding electron. Due to this, the bond order of NO increases from? 2.5 to 3 in the NO? (Nitrosonium ion).
As per the NCERT, since the bond order of NO? (3) is higher than that of NO (2.5), the bond in Nitrosonium ion is stronger bond and the stronger the bond, the shorter bond length.
Hence bond length in NO? is shorter the NO.
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