Tags Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure

Get insights from 189 questions on Chemical Bonding and Molecular Structure, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemical Bonding and Molecular Structure

Follow Ask Question

189

Questions

Discussions

Active Users

Followers

New answer posted

2 months ago

Chemical Bonding and Molecular Structure Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

If the radius of the 3^rd Bohr's orbit of hydrogen atom r₃ and the radius of 4^th Bohr's orbit is r₄. Then

0 Follower 3 Views

Payal Gupta

Contributor-Level 10

Radius of Bohr's orbit $R_{n} = 0.529 \overset{o}{A} * \frac{n^{2}}{z}$

Radius of Bohr's orbit for hydrogen, $R_{n} = 0.529 \overset{o}{A} * n^{2}$

For third orbit (R₃) = $0.529 \overset{o}{A} * 9$ = r₃ and

Fourth orbit (R₄) = $0.59 \overset{o}{A} * 16 = r_{4}$

$∴ r_{4} = \frac{16 r_{3}}{9}$

0 0

New answer posted

2 months ago

Chemical Bonding and Molecular Structure Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

Arrange the following in the decreasing order of their covalent character:

(A) LiCl
(B) NaCl
(C) KCl
(D) CsCl

0 Follower 5 Views

alok kumar singh

Contributor-Level 10

Covalent character is $L i C l > N a C l > K C l > C s C l .$ As the cationic size increases polarization decreases.

$∴$ Covalent character decreases.

0 0

New answer posted

2 months ago

Chemical Bonding and Molecular Structure Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

Given below are two statements : One is labeled as Assertion A and the other is labeled as Reason R.

Assertion A: Zero orbital overlap is an out of phase overlap.

Reason R: It results due to different orientation / direction of approach or orbitals.

...more

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

0 0

New answer posted

2 months ago

Chemical Bonding and Molecular Structure Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

The hybridization of P exhibited in PF₅ is sp^xd^y. The value of y is

0 Follower 3 Views

Payal Gupta

Contributor-Level 10

Hybridization of P in PF₅ is sp³d, so value of y = 1.

0 0

New answer posted

2 months ago

Chemical Bonding and Molecular Structure Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

Number of lone pairs of electrons in the central atom of SCl₂, O₃, ClF₃ and SF₆, respectively are:

0 Follower 1 View

Vishal Baghel

Contributor-Level 10

SCl₂ – 2 lone pair of central atom

O₃ – 1 lone pair of central atom

ClF₃ – 2 lone pair of central atom

SF₆ – 0 lone pair of central atom

0 0

New answer posted

2 months ago

Chemical Bonding and Molecular Structure Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

Which of the following pair of molecules contain odd electron molecule and an expanded octet molecule?

0 Follower 1 View

Vishal Baghel

Contributor-Level 10

BCl₃ – electron deficient molecule

SF₆ – expanded octet molecule

NO – odd electron bond containing molecule

H₂SO₄ – expanded octet molecule

0 0

New question posted

2 months ago

Chemical Bonding and Molecular Structure Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

Which of the following pair of molecules contain odd electron molecule and an expanded octet molecule?

0 Follower 1 View

New answer posted

2 months ago

Chemical Bonding and Molecular Structure Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

Which of the following is most stable?

0 Follower 3 Views

Payal Gupta

Contributor-Level 10

Aromatic species are most stable, here

0 0

New answer posted

3 months ago

Chemical Bonding and Molecular Structure Ncert Solutions Chemistry Class 11th

4.30. Which hybrid orbitals are used by carbon atoms in the following molecules?

(a) CH₃-CH₃ (b) CH₃-CH=CH₂ (c) CH₃-CH₂-OH (d) CH₃-CHO (e) CH₃COOH.

0 Follower 4 Views

Payal Gupta

Contributor-Level 10

4.30. Kindly go through the solution

0 0

New answer posted

3 months ago

Chemical Bonding and Molecular Structure Ncert Solutions Chemistry Class 11th

4.27. Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in C₂H₄ and C₂H₂molecules.

0 Follower 20 Views

Payal Gupta

Contributor-Level 10

Kindly go through the solution

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
688k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Chemical Bonding and Molecular Structure

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience