Chemistry Chemical Bonding and Molecular Structure

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alok kumar singh

Contributor-Level 10

SO3 (s) exist as cyclic trimer ⇒ S3O9

→ sp3, so all bond π–bonds would be of pπ–dπ so pπ–pπ bond = 0

pπ–dπ bonds = 6

New answer posted

6 days ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution 

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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alok kumar singh

Contributor-Level 10

Tertiary haloalkane does not undergo SN2 reaction

 

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alok kumar singh

Contributor-Level 10

He2 has zero bond order hence it does not exist.

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alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

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alok kumar singh

Contributor-Level 10

Kindly consider the following

 

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alok kumar singh

Contributor-Level 10

There are two 3-centre-2-electron bonds in B2H6.

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alok kumar singh

Contributor-Level 10

Silicon shows maximum covalency of six because 'd' orbitals take part in bonding.

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alok kumar singh

Contributor-Level 10

Kindly go through the image

 

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