Chemistry Chemical Bonding and Molecular Structure
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New answer posted
a month agoContributor-Level 10
Using VSEPR, L.P - B.P repulsion we can safely say that CH? should have the highest bond angle among the given
New answer posted
a month agoContributor-Level 10
B.O. of CO = 3
B.O. of NO? = 3
Both are isoelectronic
So difference = 0
∴ x = 0
New answer posted
a month agoContributor-Level 9
B.D.E H-H < B.D.E D-D
B.D.E H-H = 435.9 kJ / mole
B.D.E D-D = 443.4 kJ / mole
E H ≈ E D - 7.5
New answer posted
a month agoContributor-Level 10
O? = σ1s² σ1s² σ2s² σ2s² σ2pz² π2px² = π2py² π2px¹ = π2py¹
O? = σ1s² σ1s² σ2s² σ2s² σ2pz² π2px² = π2py² π2px¹
O? = σ1s² σ1s² σ2s² σ2s² σ2pz² π2px² = π2py² π2px² = π2py¹
O? ²? = σ1s² σ1s² σ2s² σ2s² σ2pz² π2px² = π2py² π2px² = π*2py²
B.O = (Bonding e? - Antibonding e? )/2
B.O of O? = (10 - 6)/2 = 2
B.O of O? = (10 - 5)/2 = 2.5
B.O of O? = (10 - 7)/2 = 1.5
B.O of O? ²? = (10 - 8)/2 = 1
New answer posted
a month agoContributor-Level 10
Not all dipole – dipole interactions are responsible for hydrogen bonding, so assertion A is false. F is most E. N atom and also hydrogen bonds in HF are symmetrical.
New question posted
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