Chemistry NCERT Exemplar Solutions Class 12th Chapter Twelve

Sol. ${\mathrm{O}}^{2-}>{\mathrm{F}}^{-}>{\mathrm{N}\mathrm{a}}^{+}>{\mathrm{M}\mathrm{g}}^{2+}$ . Greater the Zeff, smaller is size.

Sol. ${\mathrm{C}\mathrm{r}}^{2+}$ and ${\mathrm{F}\mathrm{e}}^{2+}$  both have 4 unpaired electrons.

 $\Delta E_1=-\frac{E_0}{4}+\frac{E_0}{1}=\frac{3}{4}{E}_0$

$\Delta E_2=0-\left(-E_0\right)=E_0$

$\frac{\Delta E_1}{\Delta E_2}=\frac{3}{4}$

Moles of chlorine in the given compound = Moles of chlorine in AgCl

= moles of AgCl

$n_{C\mathcal{l}}=\frac{0.4}{143.5}mo\mathcal{l}$                

Mass of chlorine = $\frac{0.4}{143.5}*35.5g$  

= 0.098 g

$\mathrm{\%}ofC\mathcal{l}=\frac{0.098}{0.25}*100=39.6\mathrm{\%}$        

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i) — (e);  (ii) — (d);  (iii) — (a);  (iv) — (b);  (v) — (f); (vi) — (c)

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i) →  (c); (ii) →  (d); (iii) →  (a); (iv) →  (b).

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i) →  (b); (ii) →  (e); (iii) →  (d); (iv) →  (a); (v) →  (c)

This is a Matching Type Questions as classified in NCERT Exemplar

 Ans: (i) →  (d); (ii) →  (e); (iii) →  (a); (iv) →  (b); (v) →  (c)

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: D

The silver mirror test can be used to determine Tollen's. [Ag (NH₃)₂] + OH ^- . Only aldehydes, not ketones, react with Tollen's reagent to create silver.

A silver mirror test is not given with this affirmative test.

The carbonyl group is present in both aldehyde and ketone.

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: C

There is no alpha hydrogen atom in the Cannizaro process. Formaldehyde and aromatic aldehydes do not contain alpha hydrogen. It proceeds through the Cannizaro reaction. Formaldehyde is the most reactive of all aldehydes.