Chemistry Organic Chemistry
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New answer posted
a week agoContributor-Level 10
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
New answer posted
a week agoContributor-Level 10
The condition for showing tautomerism by the compound is the presence of alpha hydrogen in the compound.
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