Chemistry Organic Chemistry

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A
alok kumar singh

Contributor-Level 10

Molecular formula from calculation comes to be C3H6O i.e., it stands for the following compounds.

No addition reaction with Br2

 

VD * 2 = MM         = 29 * 2 = 58

?  58 g of ether combines with 2 * 80g Br2

? 2.9 g of ether will combines with   2 * 8 0 5 8 * 2 . 9 = 8 g o f B r o m i n e

Y = 9 and X = 8

Y - X = 9 - 8 = 1

 

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Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

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Raj Pandey

Contributor-Level 9

(A) and (C) are staggered conformation. In (A) dihedral angle is 60° and in (C) dihedral angle is 180°.

Dihedral angle is angle between two specified groups.

In (C) it has maximum angle.

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New answer posted

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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Raj Pandey

Contributor-Level 9

Moles of carbon in organic compound = Moles of carbon in CO?
n_c = 420 / 44 moles
Mass of carbon in organic compound = (420 / 44) * 12 = 114.54 g
Moles of hydrogen in compound = 2 * moles of H? O
n_H = 2 * (210 / 18) moles
Mass of hydrogen = 2 * (210 / 18) g = 23.33 g
% of H = (23.33 / 750) * 100 = 3.11%
The nearest integer is 3.

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Raj Pandey

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Purification of a compound is independent of the physical state of the pure compound in chromatography techniques.

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alok kumar singh

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The partial pressure of dry N? is 758 - 14 = 744 mm Hg. Using the ideal gas law (PV=nRT), the moles of N? are calculated to be 1.25 * 10? ³ mol. This corresponds to 0.035 g of N? The percentage of nitrogen in the sample is (0.035 g / 0.1840 g) * 100, which is 18.96%.
Answer: 19 (Rounded)

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alok kumar singh

Contributor-Level 10

The Lassaign's test is a qualitative analysis method used to detect nitrogen, sulfur, phosphorus, and halogens in an organic compound. Copper (II) oxide is used to detect carbon. In the sodium fusion extract, halides (X? ) precipitate with AgNO? , and sulfide (S²? ) precipitates as black PbS.

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alok kumar singh

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B is the most acidic as it is active methylene group. D is least acidic due to crossconjugation in conjugate base.
∴ Option 3 follows

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