Chemistry Some Basic Concepts of Chemistry

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R
Raj Pandey

Contributor-Level 9

Molar mass of C7H5N3O6 = 12 * 7 + 1 * 5 + 14 * 3 + 16 * 6 = 84 + 42 + 96 = 227 g/mol

Number of moles =  6 8 1 2 2 7  = 3 mol

 number of N-atoms

= 3 * 6 . 0 2 * 1 0 2 3 * 3 = 9 * 6 . 0 2 * 1 0 2 3  

= 5 4 1 8 * 1 0 2 1  

x = 5 4 1 8  

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R
Raj Pandey

Contributor-Level 9

V (Na? CO? ) = 10 mL
Volume of HCl used will be 5 mL (average of titre values)
Meq of HCl = meq of Na? CO?
(M * n-factor * V)HCl = (M * n-factor * V)Na? CO?
0.2 * 1 * 5 = M * 2*10
M= 0.05 M
M= 50 mM

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A
alok kumar singh

Contributor-Level 10

-SO? H acts as a cation exchanger.

-NH? acts as an anion exchanger.

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A
alok kumar singh

Contributor-Level 10

C? H? + 5O? → 3CO? + 4H? O
C? H? + (13/2)O? → 4CO? + 5H? O
∴ 2 mol C? H? is given
∴ 13 mol O? is required for combustion of Butane
∴ Total mol of O? = 5 + 13 = 18

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R
Raj Pandey

Contributor-Level 9

N? + 3H? → 2NH?
(2.8 x 10³) / 28 → 0.1 x 10³ mol LR
(1 x 10³) / 2 → 0.5 x 10³ mol

Mass of NH? produced = 0.2 * 10³ * 17 = 3.4 kg = 3400 g

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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R
Raj Pandey

Contributor-Level 9

496.00

P P M =   Mass of Iron     Mass of wheat   * 10 6

Mass of 10 =   Mass of Iron   100 * 10 3 * 10 6

Mole of F e = 1 g m

F e = 1 56  contain F e S O 4 7 H 2 O  mole of  atom = 1

  F e in 1 mole

56 g  in  1 g  mole

  1 56 Mass

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