Chemistry

The shape/structure of [XeF₅]⁻ and XeO₃F₂, respectively are:

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Chemistry Chemistry Chemical Bonding and Molecular Structure

Contributor-Level 10

. [XeF? ]? has 7 electron pairs (5 bonding, 2 lone), pentagonal planar. XeO? F? has 5 electron pairs (trigonal bipyramidal).

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10 months ago

Match the type of interaction in column A with the distance dependence of their interaction energy in column B:

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Contributor-Level 10

Ion-ion ∝ 1/r. Dipole-dipole ∝ 1/r³. London dispersion ∝ 1/r?

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10 months ago

The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A graph between log(x/m) and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of x/m at a pressure of 4 atm is: [numerical value].
(Given log3 = 0.4771)

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Chemistry Ncert Solutions Chemistry Class 11th

Contributor-Level 9

Sol. (x/m) = k (P)¹/?
log (x/m) = logk + 1/n logP
Slope = 1/n = 2 So n = 1/2
Intercept ⇒ logk = 0.477 So k = Antilog (0.477) = 3
So (x/m) = k (P)¹/? = 3² = 48

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10 months ago

The internal energy change (in J) when 90 g of water undergoes complete evaporation at 100°C is
(Given: ΔH_vap for water at 373K = 41 kJ/mol, R = 8.314 JK?¹mol?¹)

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Chemistry Chemistry Coordination Compounds

Contributor-Level 9

189000 to 190000
Sol. ΔH = ΔU + Δn? RT
41000 * 5 = ΔU + 5 * 8.314 * 373
205000 = ΔU + 15505.61
ΔU = 189494.39 J = 189494 J

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10 months ago

The oxidation states of iron atoms in compounds (A), (B) and (C), respectively, are x, y and z. The sum of x,y and z is [numerical value].
(A) Na?[Fe(CN)?(NOS)], (B) Na?[FeO?], (C) [Fe?(CO)?]

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Contributor-Level 9

The oxidation states of iron in these compounds will be
A = +2
B = +4
C = 0
The sum of oxidation states will be = 6.

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10 months ago

Chemistry Structure of Atom

The number of subshells associated with n=4 and m=-2 quantum numbers is:

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Chemistry Chemistry Electrochemistry

Contributor-Level 10

For n=4, l can be 0,1,2,3. m=-2 is possible for l=2,3. So 2 subshells (4d, 4f).

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10 months ago

The Gibbs energy change (in J) for the given reaction at [Cu²?] = [Sn²?] = 1M and 298 K is Cu(s) + Sn²?(aq) → Cu²?(aq) + Sn(s); (E?Sn²?/Sn = -0.16V, E?Cu²?/Cu = 0.34 V)
Take F = 96500 Cmol?¹

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Contributor-Level 9

Sol. E? cell = E? (Sn²? |Sn) - E? (Cu²? |Cu)
= -0.16 - 0.34 = -0.50V
ΔG? = -nFE? cell
= -2 * 96500 * (-0.5) = 96500 J
= 96.5 kJ = 96500 J

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10 months ago

Consider the reaction sequence given below:

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Contributor-Level 10

Reaction (1) is SN1 (rate independent of [OH? ]). Reaction (2) is E2 (rate depends on [OH? ]).
Statement (B) is correct. Changing concentration of base will have no effect on reaction (1).

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10 months ago