Chemistry

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New answer posted

10 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

For ideal gas
PM = dRT
d = [PM]/R * 1/T
So graph between dV ST is not straight line

New answer posted

10 months ago

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R
Raj Pandey

Contributor-Level 9

In this acid base Titrating there is no use of Bunsen burner and measuring cylinder other laboratory equipments will be required for getting the end point of titration.

New answer posted

10 months ago

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R
Raj Pandey

Contributor-Level 9

In presence of sunlight CFC's molecule divides & release chlorine free radical, which react with ozone give chlorine monoxide radical (CIO°) and oxygen.
CF? Cl? (g) → C (g) + C? Cl (g)
Cl° (g) + O? (g) → ClO° (g) + O? (g)
ClO° (g) + O (g) → Cl° (g) + O? (g)

New answer posted

10 months ago

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R
Raj Pandey

Contributor-Level 9

Reaction path is SN2 because OH? is strong nucleophile, but hydroxyl ion will not attack on chiral centres and so there is retension of configuration.

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

P? V? =P? V? 48*10? ³*3³ = P? *12³. P? =750*10?

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

i of CaCl? =3. Molality eff=0.15. Molality eff of complex=0.3. [Cr (NH? )? Cl]Cl?

New answer posted

10 months ago

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R
Raj Pandey

Contributor-Level 9

Mole of Bromine = 0.08/80 = 10? ³ mole
Molar mass of compound = 0.172/M = 10? ³
M = 0.172/10? ³ = 172g
Molar mass of

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

n (KClO? )=10/122. No. of F = (10/122)*6. No. of F supplied= (100/122). t=11hrs.

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

AgBr=1.88g. Br=0.8g. %Br= (0.8/1.6)*100=50%.

New question posted

10 months ago

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