Chemistry

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New answer posted

a year ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

i of CaCl? =3. Molality eff=0.15. Molality eff of complex=0.3. [Cr (NH? )? Cl]Cl?

New answer posted

a year ago

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R
Raj Pandey

Contributor-Level 9

Mole of Bromine = 0.08/80 = 10? ³ mole
Molar mass of compound = 0.172/M = 10? ³
M = 0.172/10? ³ = 172g
Molar mass of

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

n (KClO? )=10/122. No. of F = (10/122)*6. No. of F supplied= (100/122). t=11hrs.

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

AgBr=1.88g. Br=0.8g. %Br= (0.8/1.6)*100=50%.

New question posted

a year ago

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

rate=k [Conc]? log [rate]=logk+nlog [Conc]. 'n' is slope. Higher slope, higher order.

New answer posted

a year ago

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Raj Pandey

Contributor-Level 9

(1) Pb (NO? )? → PbO + 2NO?
(2) NH? NO? → N? + 2H? O
(3) (NH? )? Cr? O? → N? + Cr? O? + H? O
(4) NaN? → 3N? + 2Na

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

µ=5.9 B.M ⇒ 5 unpaired electrons. [MnBr? ]²?

New answer posted

a year ago

0 Follower 62 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

a year ago

0 Follower 19 Views

V
Vishal Baghel

Contributor-Level 10

Δng=-1/2. Kp=Kc (RT)? ¹/². Kc=Kp (RT)¹/².

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