Chemistry

Li -> Crimson Red

Na -> Yellow

Rb -> Red violet

Cs -> Blue

VIBGYOR

Wavelength

Red violet > Crimson Red >   Yellow   >   Blue

      $\downarrow$                           $\downarrow$             $\downarrow$             $\downarrow$           

780 nm             670.8 nm     589.2 nm    455.5 nm

According to Bohr's theory,

$K.E.=13.6\frac{z^2}{n^2}$ frequency $\left(\upsilon \right)$ of revolution of electron $\propto \frac{z^2}{n^3}$

  $v=2.18*10^6\frac{z}{n}$          

$F=\frac{k{q}_1{q}_2}{r^2}=\frac{Kz{e}^2}{r^2}\left(r\propto \frac{n^2}{z}\right)$       

$F\propto \frac{z^3}{n^4}$         

If we add -NO₂ group on ortho and para position, then electron deficiency increasing in benzene ring so, order of nucleophilic attack is

Clean water would have BOD Value less than 5ppm, highly polluted water could have BOD value of 17 ppm or more.

Kindly consider the following figure

Kindly consider the following figure

S -> styrene

Buta-1, 3-diene     Styrene

Hence

CH₃ – CH₂ – CHO can't be formed.

In case of unsymmetrical alkynes, more positive charge stabilizing carbon attacked by H₂O and finally converted into carbonyl.

${\left[FeC{l}_4\right]}^{2-}\Rightarrow$

$\begin{array}{l}n=4\\ \mu =\sqrt[]{4\left(4+2\right)}\\ =4.90BM\end{array}$                                                                          

[Co (C₂O₄)₃]^3- Þ Co³⁺

Co => [Ar]4s²3d⁷

Co⁺³ = [Ar]4s⁰3d⁶

  $\mu =\sqrt[]{n\left(n+2\right)}=\sqrt[]{1\left(3\right)}=1.73BM$         

MgO has more lattice enthalpy than NaCl