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New answer posted

4 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Δ T f = 0 . 5 ° C

Kf = 1.86

Using, density of water = 1g / mL

i = ?

  Δ T f = i k f . m           

  0 . 5 = i * 1 . 8 6 * 9 . 4 5 9 4 . 5 * 5 0 0 * 1 0 0 0         

i = 1.344

Now, using α = i 1 n 1  

n for ClCH2COOH = 2

a =  1 . 3 4 4 1 2 1 = 0 . 3 4 4  

Using

K a = C α 2 1 α  

K a = 0 . 2 * ( 0 . 3 4 4 ) 3 0 . 6 6 = 3 6 * 1 0 3       

So; x = 36

New answer posted

4 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

  E o C e l l = E o A g + / A g E o Z n + 2 / Z n = 0 . 8 + 0 . 7 6 = 1 . 5 6 V

Anode :      Z n ( s ) Z n 2 + ( a q ) + 2 e

Cathode :  2Ag+(aq) + 2e- ® 2Ag(s)

Zn(s) + 2Ag+(aq) ® Zn2+ (aq) + 2Ag(s)

E c e l l = E o C e l l 0 . 0 5 9 1 n l o g [ Z n 2 + ] [ A g + ] 2 = 1 . 5 6 0 . 0 5 9 1 2 l o g ( 0 . 1 1 0 4 )    

 x = 147

 

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

4 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

Initially ->              1 mol                   -

At eq.                      1-x mol               2x mol

Here; molecules of Cl2 = atoms of Cl

i.e moles of Cl2 = moles of Cl

So : 1 – x = 2x        x = 1/3

Moles of Cl2 at equibrium =   2 3

Moles of Cl at equilibrium =   2 3

Total moles =   4 3

No

...more

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

pH = 1 2 [ p K w + p K a p K b ]

= 1 2 [ 1 4 + 4 . 7 5 5 . 2 3 ]

= 6 . 7 6 7

 

New answer posted

4 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Uncertainty in speed = 90 * 5 1 0 0 = 4 . 5 m / s = Δ V

Δ x = h 4 π m Δ V = 6 . 6 3 * 1 0 3 4 4 * 3 . 1 4 * 1 0 2 * 4 . 5 = 1 . 1 7 3 * 1 0 3 3

the nearest integer is 1

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Fraction of molecules having enough energy to form product = e E a / R T

Fraction of molecules having enough energy to form product = e 8 0 . 9 * 1 0 3 8 . 3 1 4 * 7 0 0

= e 1 3 . 8 e 1 4

So, x = 14

New answer posted

4 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

A (g) -> B (g)        KP = 100

Δ G at 300 K and 1 atm

Using

Δ G = R T l n K P           

Δ G = R * 3 0 0 l n 1 0 0            

=-R * 300 * 2 * 2.3

Δ G = 1 3 8 0 R            

So; x = 1380.

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Δ T f = K f * m * i

0.93 = 1.86 * 1 * i

i = 1 2 i = 1 + ( 1 n 1 )

n = 2

New answer posted

4 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Stability constant are :

K1 = 104

K2 = 1.58 * 103

K3 = 5 * 102

K4 = 102

Overall stability constant K will be

K = K1 * K2 * K3 * K4

 = 7.9 * 1011

Now, overall equilibrium constant for dissociation of [Cu (NH3)4]2+ is

K ' = 1 K = 1 7 . 9 * 1 0 1 1 = 0 . 1 2 6 * 1 0 1 1  

= 1.26 * 10-12

So; x = 1 (Rounded off to the nearest integer)

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