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Chemistry Equilibrium

A(g) ->B(g) + $\frac{1}{2}$ C(g)

In the about reaction, the correct relation between K_p, a and equilibrium pressure (p) is

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alok kumar singh

Contributor-Level 10

A(g) ->B(g) + $\frac{1}{2}$ (g)

Initial moles n 0 0

Eqb. moles n(1 – a) $\frac{n α}{2}$ n_a

total moles = $n (1 + \frac{α}{2})$

Eqb. pressure $\frac{(1 - α) p}{1 + \frac{α}{2}}$ $\frac{α p}{1 + \frac{α}{2}}$ $\frac{(\frac{α}{2}) p}{1 + \frac{α}{2}}$

$\frac{K_{p} = \frac{α p}{(1 + \frac{α}{2})} * {[\frac{α p}{(2 + α)}]}^{\frac{1}{2}}}{\frac{(1 + α) p}{1 + \frac{α}{2}}}$

$K_{p} = \frac{α^{\frac{3}{2}} p^{\frac{1}{2}}}{{(2 + α)}^{\frac{1}{2}} (1 - α)}$ &nbs

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A(g) ->B(g) + $\frac{1}{2}$ (g)

Initial moles n 0 0

Eqb. moles n(1 – a) $\frac{n α}{2}$ n_a

total moles = $n (1 + \frac{α}{2})$

Eqb. pressure $\frac{(1 - α) p}{1 + \frac{α}{2}}$ $\frac{α p}{1 + \frac{α}{2}}$ $\frac{(\frac{α}{2}) p}{1 + \frac{α}{2}}$

$\frac{K_{p} = \frac{α p}{(1 + \frac{α}{2})} * {[\frac{α p}{(2 + α)}]}^{\frac{1}{2}}}{\frac{(1 + α) p}{1 + \frac{α}{2}}}$

$K_{p} = \frac{α^{\frac{3}{2}} p^{\frac{1}{2}}}{{(2 + α)}^{\frac{1}{2}} (1 - α)}$

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Chemistry Class 12th

Consider the following reaction.

Select P

(Where Me is CH₃)

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alok kumar singh

Contributor-Level 10

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New answer posted

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Chemistry Class 12th

Statement-I : Aniline on reaction with concentrated H₂SO₄ at 475 K gives p-amino benzene sulphonic acid. This gives blood red colour with Lassaigne's test.

Statement-II : Aniline forms a salt with anhydrous AlCl₃ in Friedel Craft's reaction.

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