Chemistry

As NaCl is strong electrolyte, its degree of dissociation (a) will remain same.

            I = 2

            For each sample,

            i₁ = i₂ = i₃

$pH=\frac{p{K}_w+p{K}_a?p{K}_b}{2}$

pK_a = pK_b

$pH=\frac{p{K}_w}{2}=7$

Adenine base pairs with thymine with 2 hydrogen bonds and cytosine base pairs with guanine with 3 hydrogen bonds.

The balanced reaction is.

            Cr₂  + 14H⁺ + 6e^– ® 2Cr³⁺ + 7H₂O

            x = 14

            y = 6

            A = 7

$?=\frac{h}{p}\left[??\frac{1}{p}\right]$

Þ        lp = h (constant)

            So, the plot is a rectangular hyperbola.

q = 0 as adiabatic process is given

            W = 0 as p_axt = 0

            q + W = DU

            q = 0

            W = 0

            Þ DU = 0

PF₅, PCl₅, PBr₅, Fe (CO)₅ Þ Trigonal bipyramidal

BrF₅ Þ Square pyramidal

[PtCl₄]^2– Þ Square planar

SF₆ Þ Octahedral

Boiling point: $\stackrel{\left(239.7\right)}{N{H}_3}>\stackrel{\left(185.5\right)}{P{H}_3}$  due to hydrogen bonding in NH₃.

Order of reactivity towards electrophile

Strength of +M/+R : –OH > –CH₃ > –Cl

In case of halogens, their –I effect dominates over

+M hence –Cl is deactivating and  is lesser reactive than  for incoming electrophile.