Chemistry

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New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

[Ni (H2O)6]2+ Þ Ni2+ is octahedral and [Ni (CN)4]2– is square planar.

In [Ni (H2O)6]2+ Þ Ni2+ has two unpaired electrons and in [Ni (CN)4]2– Þ Ni2+ has no unpaired electrons. [Ni (H2O)6]2+ is coloured as it absorbs red light due to suitable d-d transition and complementary light emitted is green.

[Ni (CN)4]2– has strong field ligand so the electrons of Ni2+ pair up and it is colourless as it cannot absorb light from visible region.

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

PbS + 4H2O2->PbSO4 + 4H2O.

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

Work depends on the path followed by the system so work is path function.

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

Since VReal > Videal

So, Z = VReal > 1. Videal

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

KCN   + CN

            R – X + KCN  R – CN + KX

            R – X + AgCN  R – NC + AgX

            KCN is ionic therefore ionised and attack occurs through carbon.

            AgCN is covalent therefore attack starts with Nitrogen.

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

meq. of K2Cr2O7 = meq. of NO2

n1 * 6 = 1 * 2

n1=1/3

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

C v m = 2 ( 3 R 2 ) + 6 ( 5 R 2 ) 2 + 6

= 3 R + 1 5 R 8 = 1 8 R 8

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

Radial nodes = n –? – 1 = 3 – 1 – 1 = 1

Angular nodes =? = 1.

New answer posted

9 months ago

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alok kumar singh

Contributor-Level 10

Please find the solution below:
 

 

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