Chemistry
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New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Due its disintegration into oxygen results in the release of heat ΔH is negative) and an increase in entropy (ΔS is positive), ozone is thermodynamically unstable in comparison to oxygen. These two reactions combine to produce a substantial negative Gibbs energy change (ΔG) for its conversion to oxygen.
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Oxygen is more electronegative than chlorine, the negative charge on chlorine disperses from ClO− to ClO4− ion as the number of oxygen atoms linked to chlorine grows. As a result, ion stability will improve in the following order:
As the stability of the conjugate base rises, the acidic strength of the corresponding acid increases in the following order:
HClO < HClO2 < HClO3 < HClO4
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
NO3− + 3Fe2+ + 4H+→ NO+ + 3Fe3+ + 2H2O
[Fe (H2O)6]2+ + NO → [Fe (H2O)5 (NO)]2+ + H2O ( brown ring )
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a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
A is PCl5 (yellowish white powder)
P4 + 10Cl2→4PCl5
B is PCl3 (colourless oily liquid)
Hydrolysis of the following product
PCl3+3H2O→H3PO3+3HCl
PCl5+4H2O→H3PO4+5HCl
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Six F atoms can be accommodated around sulphur due to fluorine's tiny size, however the chloride ion is comparably bigger, resulting in interatomic repulsion.
New question posted
a year agoNew answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Oxygen is more electronegative than sulphur, the bond angle of H2O is greater, and the bod pair electron of an OH bond will be closer to oxygen, causing bond-pair repulsion between bond pairs of two OH bonds
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Chlorine has vacant d-orbitals, which become excited upon bonding when electrons from the 3p-orbital are promoted to the 3d-orbital, giving it a covalency of three.
Due to the lack of unoccupied d-orbitals in the second energy shell, fluorine cannot expand its octet. As a result, it can only have one covalency.
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
NO2 exists as a monomer with one unpaired electron in the gaseous state, but it dimerises to N2O4 in the solid state, leaving no unpaired electron, making the solid form diamagnetic.
New answer posted
a year agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Three P—Cl bonds are arranged in one plane at a 1200 angle. These bonds are known as equatorial bonds because they are formed between two points. The remaining two P—Cl bonds, one above the equatorial plane and the other below it, form 90° angle with the plane. Axial bonds are the name for these types of bonds. Because axial bond pairs are subjected to greater repulsive interaction than equatorial bond pairs, axial bonds are slightly longer and hence slightly weaker than equatorial bonds, making the PCl5 molecule more reactive.

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