Chemistry

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New answer posted

a year ago

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P
Payal Gupta

Contributor-Level 10

4.16 Increase in temperature increases the rate constant of a reaction. as we know increase in temperature increases the rate of reaction to satisfy the equation Rate = k [concentration]n where n can be any real number. k have to increase as concentration is almost not changing over small temperature change.

Increasing the temperature by 10°c almost doubles the rate constant. This can be represented quantitatively by the help of the Arrhenius equation-

K = Ae-Ea/RT, where k is rate constant, Ea is the activation energy, R is the universal gas constant, T is the absolute temperature.

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

5.6 

Desorption is a process in which substance (reactant + product) is released from the surface which is the opposite process of sorption.

The role of desorption in the process of catalysis is to make the surface of the solid catalyst-free for fresh adsorption of reactants on the solid surface for further reactions to take place.

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

The complex is an anion with chromium as central atom, 2 water molecules and 2 oxolate ions with -2 negative charge Balance overall charge as 0, we get oxidation state of Cr as:

X + 2 (0) + 2 (-2) = -1 X = + 3.

Name of compound: potassium diaquadioxolatochromate (III) trihydrate. Electronic configuration of Cr: 3d3, t2g3

New answer posted

a year ago

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Payal Gupta

Contributor-Level 10

4.15 Let suppose reaction 

A? B; having rate law, Rate = K [A]2

(i) If the concentration of A is doubled then the rate will affect by the square of concentration i.e. rate will become 22 = 4 times.

(ii) If the concentration of A is halved, then the rate will affect the square of the concentration i.e (1/2)2 = 1/4

(i) Rate becomes 4 times of initial Rate (ii) Rate becomes 1/4 times of initial Rate

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

(i) Overall charge balance:

X + 3 (-2) = -3 X = + 3

Oxidation state of Co is + 3.

As there are 3 oxolate ion and being bidentate, coordination no. Of complex is 6. So it is octahedral complex.

d orbital occupation: t2g6eg0 (oxolate ion is weak field ligand, does not cause pairing of electron as the energy required for pairing of electron is more than CFSE).

 

(ii) Overall charge balance:

X + balance4 (-1) = -2 X = + 2

Oxidation state of Co is + 2.

As there are 4 fluoride ion, coordination no. Of complex is 4 i.e. Tetrahedral complex.

d orbital occupation: eg4t2g3 (fluoride ion is weak field ligand, does not cause pairing of electron as th

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New answer posted

a year ago

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Payal Gupta

Contributor-Level 10

4.14 Factors affecting rate of reaction-

1) Temperature (increasing temperature increases rate of reaction)

2) Concentration or pressure of reactants. (Increasing concentration or pressure increases rate of reaction)

3) Presence or absence of a (Adding catalyst mostly increases the rate of reaction)

4) The surface area of solid (If reaction is processing over solid reactant then increasing its surface area increases rate of reaction)

5) Nature of reactants

New answer posted

a year ago

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alok kumar singh

Contributor-Level 10

5.5

Ester hydrolysis is represented as:

Ester + Water → Acid + Alcohol

In this reaction the acid produced which is a product also acts as a catalyst and makes the reaction faster.

Such substances that act as catalysts in the same reaction in which they are obtained as products are known as Autocatalysts.

So, ester hydrolysis is slow in the beginning and becomes faster after some time as more acid is produced on the product side.

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a year ago

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Payal Gupta

Contributor-Level 10

4.13 Rate of given chemical reaction will be represented as

-d [pCH3OCH3] / dt

Hence units of rate is bar min-1

To find units of K, K = rate/ [pCH3OCH3]3/2

The unit of k = bar -1/2min-1.

Units of Rate- bar min-1. and Units of Rate constant K : bar -1/2min -1

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Compounds containing carbonyl

Ligands only are known as homoleptic carbonyl. Such types of compounds are formed by most of the transition metals. These metal carbonyls always have simple, well-defined structures. In metal carbonyls the metal - carbonyl bond possess both s and p.character. M-C-bond is sigma bond. It is formed by the donation of lone pair of electrons of the carbonyl carbon into the vacant orbital of the metal. The M-C pi bond is formed by the donation of a pair of electron from a filled d orbital of a metal into the vacant antibonding? orbital of carbon monoxide. Such type of metal to ligand bonding creates a synergic ef

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a year ago

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alok kumar singh

Contributor-Level 10

5.4

It is important to remove CO (Carbon Monoxide) in the synthesis of ammonia as CO affects the activity of Iron catalyst which is required in Haber's process.

Note: Haber's process is a very important industrial process which is used to produce ammonia.

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