Chemistry
Get insights from 6.9k questions on Chemistry, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
11 months agoContributor-Level 10
9.35. Bleaching action of H2O2 is due to the oxidation of colouring matter by nascent oxygen.
H2O2→ H2O + O
New answer posted
11 months agoContributor-Level 10
9.34. KCl is a salt of strong acid HCl and strong base KOH. Such salts are neutral in nature and do not undergo hydrolysis. In neutral water, acidic water, and alkaline water, KCl dissociates as
Water
KCl → ?K++Cl−
AlCl3? is a salt of strong acid HCl and weak base Al(OH)3?.
(i) In normal water, it is hydrolyzed.
AlCl3?+3H2?O→Al(OH)3?+3H++3Cl−
(ii) In acidic water, H+ ions react with Al(OH)3? (obtained from the hydrolysis of AlCl3?) forming water and Al3+ ions. Hence it exists as Al3++Cl−
AlCl3? + acidifiedwater? → Al++3Cl−
(iii) In alkaline wa
New answer posted
11 months agoContributor-Level 10
11.80
The preparation of ether by acid dehydration of primary alcohol involves the nucleophilic addition of alcohol molecule to the protonated alcohol molecule as shown below: -
However, under these conditions secondary and tertiary alcohols forms alkenes rather than ethers. The reason for this being that due to stearic hindrance, nucleophilic attack by the alcohol molecule on the protonated alcohol molecule does not take place. Instead protonated 20 and 30 alcohols lose a molecule of water to form stable carbocations. The stable carbocations so formed prefers to lose a proton to form alkenes instead of forming ethers by undergoing
New answer posted
11 months agoContributor-Level 10
9.33. Atomic number 15 is of phosphorus. The hydride is PH3 and its nature is covalent. Atomic number = 19 is of potassium. The hydride is KH and it is ionic in nature. Atomic number = 23 is of vanadium. The hydride is VH. It is interstitial or metallic. Atomic number =44 is of ruthenium, its hydride is interstitial or metallic.
New answer posted
11 months agoContributor-Level 10
9.32. Saline hydrides (i.e. CaH2 NaH etc.) react with water and form the corresponding metal hydroxide with the liberation of H2 gas. Thus, these hydrides can be used to remove traces of water from the organic compounds.
NaH (s) + H2O (l) → NaOH (aq) + H2 (g)
CaH2 (s) + 2H2O (l) → Ca (OH)2 (aq) + H2 (g)
New answer posted
11 months agoContributor-Level 10
11.79
According to the question we have to perform the following conversion: -
The mechanism of the above reaction is as follows : - The mechanism is given below: -
In the first step, the alcohol gets protonated by the acid present to give a protonated alcohol.
In the second step, the nucleophilic attack of another alcohol molecule on the protonated alcohol gives us 1-propoxypropane as the desired product.
New answer posted
11 months agoContributor-Level 10
9.31. (H+ and OH− ions) of water molecule react with a compound to form products. For example:
NaH+H2O → NaOH+H2
Hydration is defined as the addition of one or more water molecules to ions or molecules to form hydrated compounds. For example:
CuSO4+5H2O → CuSO4.5H2O
New answer posted
11 months agoContributor-Level 10
11.78
Williamson synthesis is basically a SN2 reaction of a primary alkyl halide with an alkoxide ion. The basic mechanism for this reaction is
Now consider this reaction,
This reaction proceeds as conventional Williamson synthesis. But if secondary or tertiary alkyl halides are taken in place of primary alkyl halides, then elimination would compete over substitution reaction, which will result in the formation of alkenes. The reason is alkoxides are better nucleophiles as well as strong bases. Therefore, they react with alkyl halides resulting in an elimination reaction.
New answer posted
11 months agoNew answer posted
11 months agoContributor-Level 10
11.77
During the reaction, an alkoxide ion is formed which is then added to an alkyl halide to form the ether via SN2 mechanism.
In the primary step, the nucleophile is formed (O- ) which will the approach to the alkyl halide and after the transition stage, the substitution takes place.
During the reaction, an alkoxide ion is formed which is then added to an alkyl halide to form the ether via SN2 mechanism.
During the reaction, an alkoxide ion is formed which is then added to an alkyl halide to form the ether via SN2 mechanism.
During the reaction, an alkoxide ion is formed which is then added to an alkyl halide to form the ether via
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 688k Reviews
- 1850k Answers