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alok kumar singh

Contributor-Level 10

11.83 

The reaction of HI with methoxymethane yields two different sets of products depending upon the initial amount of HI taken.

When equal moles of HI and methoxymethane are taken, a mixture of methyl alcohol and methyl iodide is

The mechanism is given below:

In the first step, methoxymethane reacts with hydrogen iodide to extract a proton to give the dimethyloxonium ion.

In the second step of the reaction, the Dimethyloxonium ion reacts with the iodide ion present to yield methyl iodide and methyl alcohol as the product via SN2 pathway.

If an excess of HI is used the methyl alcohol formed in Step II is also converted into methyl iod

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a year ago

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alok kumar singh

Contributor-Level 10

11.82

(i) In aryl alkyl ethers the +R effect of the alkoxy group leads to an increase in the electron density of the benzene ring as they push electrons into the ring making the benzene ring activated towards electrophilic substitution reactions. This could be understood more clearly from the following resonating structures : -

(ii) It could be clearly seen from the above resonating structures that the electron density increases more at the ortho and para positions as compared to the meta positions. Hence, we can conclude that the alkoxy group directs the incoming substituents to ortho and para positions in the benzene ring.

For example

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alok kumar singh

Contributor-Level 10

11.81 

1-propoxypropane reacts with hydrogen iodide to give propan-1-ol and 1-iodopropane as the products.

2. Methoxybenzene reacts with hydrogen iodide to give phenol and iodomethane

Benzyl ethyl ether reacts with hydrogen iodide to give benzyl iodide and ethanol

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Payal Gupta

Contributor-Level 10

9.36.  (i) Hydrogen economy: The basic principle of hydrogen economy is the storage and transportation of energy in the form of liquid or gaseous dihydrogen.

(ii) Hydrogenation: Hydrogenation means addition of hydrogen across double and triple bonds in presence of catalyst to form saturated compounds.

(iii) Syngas: The mixture of CO and H2 are called synthesis gas or 'syngas'. It can be produced by the reaction of steam on hydrocarbon or coke at high temperature in the presence of nickel catalyst

(iv) Water-gas shift reaction: The amount of hydrogen in the syngas can be increased by the action of CO of syngas m

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Payal Gupta

Contributor-Level 10

9.35. Bleaching action of H2O2 is due to the oxidation of colouring matter by nascent oxygen.
H2O2→ H2O + O

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Payal Gupta

Contributor-Level 10

9.34. KCl is a salt of strong acid HCl and strong base KOH. Such salts are neutral in nature and do not undergo hydrolysis. In neutral water, acidic water, and alkaline water, KCl dissociates as
      Water

KCl → ?K++Cl−
AlCl3? is a salt of strong acid HCl and weak base Al(OH)3?.

(i) In normal water, it is hydrolyzed.
AlCl3?+3H2?O→Al(OH)3?+3H++3Cl−

(ii) In acidic water, H+ ions react with Al(OH)3?  (obtained from the hydrolysis of AlCl3?) forming water and Al3+ ions.  Hence it exists as Al3++Cl−
AlCl3? + acidifiedwater? → Al++3Cl−

(iii) In alkaline wa

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alok kumar singh

Contributor-Level 10

11.80 

The preparation of ether by acid dehydration of primary alcohol involves the nucleophilic addition of alcohol molecule to the protonated alcohol molecule as shown below: -

However, under these conditions secondary and tertiary alcohols forms alkenes rather than ethers. The reason for this being that due to stearic hindrance, nucleophilic attack by the alcohol molecule on the protonated alcohol molecule does not take place. Instead protonated 20 and 30 alcohols lose a molecule of water to form stable carbocations. The stable carbocations so formed prefers to lose a proton to form alkenes instead of forming ethers by undergoing

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Payal Gupta

Contributor-Level 10

9.33. Atomic number 15 is of phosphorus. The hydride is PH3 and its nature is covalent. Atomic number = 19 is of potassium. The hydride is KH and it is ionic in nature. Atomic number = 23 is of vanadium. The hydride is VH. It is interstitial or metallic. Atomic number =44 is of ruthenium, its hydride is interstitial or metallic.

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a year ago

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Payal Gupta

Contributor-Level 10

9.32. Saline hydrides (i.e. CaH2 NaH etc.) react with water and form the corresponding metal hydroxide with the liberation of H2 gas. Thus, these hydrides can be used to remove traces of water from the organic compounds.

NaH (s) + H2O (l) → NaOH (aq) + H2 (g)

CaH2 (s) + 2H2O (l) → Ca (OH)2 (aq) + H2 (g)

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a year ago

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alok kumar singh

Contributor-Level 10

11.79 

According to the question we have to perform the following conversion: -

The mechanism of the above reaction is as follows : - The mechanism is given below: -

In the first step, the alcohol gets protonated by the acid present to give a protonated alcohol.

In the second step, the nucleophilic attack of another alcohol molecule on the protonated alcohol gives us 1-propoxypropane as the desired product.

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