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11 months agoContributor-Level 10
11.62
The conversion of Phenol from Cumene requires the air oxidation of:
The air oxidation of cumene (isopropyl benzene) leads to the production of both phenol and acetone (costlier than phenol).
The air oxidation of cumene gives cumene hydro peroxide as an intermediate which on further hydrolysis (H3O+) gives phenol and acetone.
New answer posted
11 months agoContributor-Level 10
9.13. When hydrogen is burnt in oxygen the reaction is highly exothermic, it produces very high temperature nearly 4000°C which is used for cutting and welding purposes.
New answer posted
11 months agoContributor-Level 10
9.12. Metallic hydrides are useful for ultra-purification of dihydrogen and as dihydrogen storage media. In metallic hydrides, hydrogen is adsorbed as H-atoms. Due to the adsorption of H atoms the metal lattice expands and become unstable. Thus, when metallic hydride is heated, it decomposes to form hydrogen and finely divided metal. The hydrogen evolved can be used as fuel.
New answer posted
11 months agoContributor-Level 10
11.61
In ortho nitrophenol there is intra-molecular H bonding, whereas in para-nitrophenol there is inter-molecular H bonding, as shown below:
And because of that para-nitrophenol get tightly bounded with water and ortho nitrophenol is steam volatile and it will leave the solution.
New answer posted
11 months agoContributor-Level 10
9.11. Those hydrides which do not have fix composition are called non-stoichiometric hydrides, and the composition varies with temperature and pressure. This type of hydrides is formed by d- and f-block elements. They cannot be formed by alkali metals because alkali metal hydrides form ionic hydrides.
New answer posted
11 months agoContributor-Level 10
11.60
The different forms of cresol is formed with given molecular formula:
2-methylphenol
3-methylphenol
4-methylphenol
New answer posted
11 months agoContributor-Level 10
11.58
The hydroboration-oxidation reaction is a two-step reaction that converts an alkene into a neutral alcohol by the net addition of water across the double bond. The hydrogen and hydroxyl group are added in a syn addition leading to the cis configuration. Hydroboration- oxidation is an anti-Markovnikov reaction, with the hydroxyl group attaching to the less substituted carbon. In first step Addition of Hydroborate group is done and in next step, it is oxidized by hydrogen peroxide.
For example: - When propene undergoes hydroboration-oxidation reaction, then it produces propan-1-ol as product. In this reaction diborane i.e., (BH3)2 re
New answer posted
11 months agoContributor-Level 10
11.57
Due to the presence of –OH group, alcohols form hydrogen-bonds with water but hydrocarbons cannot form hydrogen-bonds with water.
Due to inter moleculer hydrogen bonding between Alcohol and water molecular they remain tightly bounded to water molecules and have higher solubility. Whereas in case of hydrocarbon there is no chance of hydrogen bonding.
New answer posted
11 months agoContributor-Level 10
11.56
Here, propanol undergoes intermolecular H-bonding because of the presence of -OH group while butane has no such property
(intermolecular Hydrogen bonding in propanol)
Therefore, extra energy will be required to break those hydrogen bonds which in turn causes higher boiling point for propanol when compared to butane.
New answer posted
11 months agoContributor-Level 10
9.10. Carbon hydrides of the type CnH2n+2 are electron precise hydrides. Because they have atom with exact number of electrons to form covalent bonds. Thus, they do not behave as Lewis acid or base. Since they have no tendency to accept or lose electrons.
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