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New answer posted
a year agoContributor-Level 10
11.64
Step 1:- Protonation of ethene to form carbocation by electrophilic attack of H3O+.
Step 2:- Nucleophilic attack of water on carbocation.
Step 3:- Deprotonation to form ethanol.
New answer posted
a year agoContributor-Level 10
There are many ways to this conversion. Two of them are given below:-
11.63
(a) In the above conversion, the chlorobenzene is treated with a base such as NaOH, KOH etc. (strong base). The base abstracts the hydrogen from the C-2 position (it can also abstract the hydrogen from the C-6 position, as both are equally acidic) leaving the negative charge at that position.
In the next step Cl- leaves, leaving behind the positive charge at that carbon. Both the negative charge and positive charge forms a bond resulting Benzyne as the intermediate.
After the formation of the Benzyne intermediate OH- of the base attacks at the C-1 position and fur
New answer posted
a year agoContributor-Level 10
9.15. No. Because if saline hydrides react with water the reaction will be highly exothermic thus the hydrogen evolved in this case can catch fire. CO2 cannot be used as fire extinguisher because CO2 will get absorbed in alkali metal hydroxides.
New answer posted
a year agoContributor-Level 10
9.14. HF is expected to have the highest magnitude of hydrogen bonding since, fluorine is most electronegative. Therefore, HF is the most polar.
New answer posted
a year agoContributor-Level 10
11.62
The conversion of Phenol from Cumene requires the air oxidation of:
The air oxidation of cumene (isopropyl benzene) leads to the production of both phenol and acetone (costlier than phenol).
The air oxidation of cumene gives cumene hydro peroxide as an intermediate which on further hydrolysis (H3O+) gives phenol and acetone.
New answer posted
a year agoContributor-Level 10
9.13. When hydrogen is burnt in oxygen the reaction is highly exothermic, it produces very high temperature nearly 4000°C which is used for cutting and welding purposes.
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a year agoContributor-Level 10
9.12. Metallic hydrides are useful for ultra-purification of dihydrogen and as dihydrogen storage media. In metallic hydrides, hydrogen is adsorbed as H-atoms. Due to the adsorption of H atoms the metal lattice expands and become unstable. Thus, when metallic hydride is heated, it decomposes to form hydrogen and finely divided metal. The hydrogen evolved can be used as fuel.
New answer posted
a year agoContributor-Level 10
11.61
In ortho nitrophenol there is intra-molecular H bonding, whereas in para-nitrophenol there is inter-molecular H bonding, as shown below:
And because of that para-nitrophenol get tightly bounded with water and ortho nitrophenol is steam volatile and it will leave the solution.
New answer posted
a year agoContributor-Level 10
9.11. Those hydrides which do not have fix composition are called non-stoichiometric hydrides, and the composition varies with temperature and pressure. This type of hydrides is formed by d- and f-block elements. They cannot be formed by alkali metals because alkali metal hydrides form ionic hydrides.
New answer posted
a year agoContributor-Level 10
11.60
The different forms of cresol is formed with given molecular formula:
2-methylphenol
3-methylphenol
4-methylphenol
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