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New answer posted
a year agoContributor-Level 10
11.58
The hydroboration-oxidation reaction is a two-step reaction that converts an alkene into a neutral alcohol by the net addition of water across the double bond. The hydrogen and hydroxyl group are added in a syn addition leading to the cis configuration. Hydroboration- oxidation is an anti-Markovnikov reaction, with the hydroxyl group attaching to the less substituted carbon. In first step Addition of Hydroborate group is done and in next step, it is oxidized by hydrogen peroxide.
For example: - When propene undergoes hydroboration-oxidation reaction, then it produces propan-1-ol as product. In this reaction diborane i.e., (BH3)2 re
New answer posted
a year agoContributor-Level 10
11.57
Due to the presence of –OH group, alcohols form hydrogen-bonds with water but hydrocarbons cannot form hydrogen-bonds with water.
Due to inter moleculer hydrogen bonding between Alcohol and water molecular they remain tightly bounded to water molecules and have higher solubility. Whereas in case of hydrocarbon there is no chance of hydrogen bonding.
New answer posted
a year agoContributor-Level 10
11.56
Here, propanol undergoes intermolecular H-bonding because of the presence of -OH group while butane has no such property
(intermolecular Hydrogen bonding in propanol)
Therefore, extra energy will be required to break those hydrogen bonds which in turn causes higher boiling point for propanol when compared to butane.
New answer posted
a year agoContributor-Level 10
9.10. Carbon hydrides of the type CnH2n+2 are electron precise hydrides. Because they have atom with exact number of electrons to form covalent bonds. Thus, they do not behave as Lewis acid or base. Since they have no tendency to accept or lose electrons.
New answer posted
a year agoContributor-Level 10
9.9. It is expected to be a Lewis acid. They are likely to accept electrons to become stable. They can form coordinate bond with electron rich compound.
2NaH(s) + B2H6 (g) → 2Na+[BH4]- (s)
&n
New answer posted
a year agoContributor-Level 10
11.55
The structures of all isomeric alcohols of C5H12O are given below:
Naming is done by the conventional method. The -OH group is attached on the first carbon.
(b) 3-Methylbutan-1-ol
Butane is the longest chain and methyl is the substituent group.
(c) 3-Methylbutan-1-ol
the longest chain is butane and conventional naming method is used.
(d) 2,2-Dimethylpropan-1-ol
Isomer is made by transforming the principal carbon into tertiary type. The longest chain is butane and named accordingly.
(e) Pentan-2-ol
the longest chain is pentane and the numbering is chosen from the minimum position.
(f) 3-Methylbutan-2-ol
Butane is the longest chain,
New answer posted
a year agoContributor-Level 10
9.8. (i) Electron deficient hydrides: Compounds in which central atom has incomplete octet, are called electron deficient hydrides. For example, BeH2, BH3 are electron deficient hydrides.
(ii) Electron precise hydrides: Those compounds in which exact number of electrons are present in central atom or the central atom contains complete octet are called precise hydrides e.g., CH4, SiH4, GeH4 etc. are precise hydrides.
(iii) Electron rich hydrides: Those compounds in which central atom has one or more lone pair of excess electrons are called electron rich hydrides, e.g., NH3, H2O.
New answer posted
a year agoContributor-Level 10
9.7. This is due to its small atomic size and small bond length (74 pm) of H-H bond.H? H bond has very high bond enthalpy (435.9 kJ/mol) which results in low reactivity at room temperature. The reactivity is increased at high temperature or in presence of catalyst. Under these conditions, hydrogen reacts with many metals and non-metals to form hydrides.
New answer posted
a year ago
Contributor-Level 10
9.6. (i) 3H2?(g)+2MoO3? ? Mo2?O3?+3H2?O(l)
(ii) CO (g) + H2 (g) ? CH3OH
(iii) C3H8 (g) + 3H2O(g) ? 3CO + 7H2(g)
(iv) Zn (s) + NaOH (aq) ? Na2ZnO2(s) + H2(g)
New answer posted
a year agoContributor-Level 10
11.54
Butane is the longest chain.
Propane is principle chain and substituents are numbered accordingly.
Hexane is the longest chain. There are three -OH substituents and 2 methyl groups.
-OH of phenol is numbered a 1.
Propane is the principle chain and the alkoxy group is ethyl group.
the longest chain is pentane and substituents are numbered accordingly.
In such cases, cyclo groups are named first, followed by conventional naming methods.
The cyclo group is named first, followed by conventional naming methods.
The longest chain is butane when looked for minimum numbering case.
Cyclo group is named first. Pentane having a double bond is named
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