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Chemistry Chemistry Coordination Compounds

Given below are two statements:

Statement I : In CuSO₄.5H₂O, Cu-O bonds are present

Statement II : In CuSO₄.5H₂O, ligands coordinating with Cu(II) ion are O- and S- based ligands

In the light of the above statements, choose Correct answer from the options given below:

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alok kumar singh

Contributor-Level 10

From the given structure of CuSO₄. 5H₂O Cu (II) ion and oxygen bonds are present but ligands coordinating with Cu (II) ion are not O and S both.

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Chemistry Class 12th

Match List – I with List – II:

List – I (Ore) List – II (Composition)

(A) Siderite

...more

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alok kumar singh

Contributor-Level 10

Ore Formula

Siderite FeCO₃

Malachite &n

...more

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3 months ago

Chemistry Chemistry Classification of Elements and Periodicity in Properties

Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R.

Assertion (A) : The first ionization enthalpy for oxygen is lower than that of nitrogen

Reason (R) : The four electrons in 2p orbitals of oxygen experience more electron electorn repulsion.

In the light of the above statements, choose the correct answer from the options given below:

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alok kumar singh

Contributor-Level 10

1^st ionization energy of N>O in oxygen atom, 2 electrons out of 4 electron of 2p orbital resulting in an increased electron repulsion.

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Chemistry Class 12th

A 42.12% (w/v) solution of NaCl causes precipitation of a certain sol in 10 hours. The coagulating value of NaCl for the sol is

[Given molar mass : Na = 23.0g mol^-¹; Cl = 35.5g mol^-¹]

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alok kumar singh

Contributor-Level 10

Data is not sufficient but official answer is (D)

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Chemistry Equilibrium

4.0 moles of argon and 5.0 moles of PCl₅ are introduced into an evacuated flask of 100 litre capacity at 610 K. The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be 6.0 atm. The K_P for the reaction is

[Given R = 0.082 L atm K^-¹ mol^-¹]

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alok kumar singh

Contributor-Level 10

Moles of PCl₅ = 5 mol

Moles of Ar = 4 mol

Total no of moles = 9 moles

$P_{T o t a l} = \frac{n R T}{V} = \frac{9 * 0.0821 * 610}{100} = 4.5 a t m$

$P_{P C l_{5}} = X_{P C l_{5}} * P_{T} = \frac{5}{9} * 4.5 = 2.5 a t m$

$P_{A r} = X_{A r} * P_{T} = \frac{4}{9} * 4.5 = 2 a t m$

$P C l_{5} \overset{}{?} P C l_{3} + C l_{2}$

2.5 0 0

2.5 - P P P

$P_{T o t a l} = 2.5 - P + P + P + P_{A r} = 6$

P = 1.5

...more

Moles of PCl₅ = 5 mol

Moles of Ar = 4 mol

Total no of moles = 9 moles

$P_{T o t a l} = \frac{n R T}{V} = \frac{9 * 0.0821 * 610}{100} = 4.5 a t m$

$P_{P C l_{5}} = X_{P C l_{5}} * P_{T} = \frac{5}{9} * 4.5 = 2.5 a t m$

$P_{A r} = X_{A r} * P_{T} = \frac{4}{9} * 4.5 = 2 a t m$

$P C l_{5} \overset{}{?} P C l_{3} + C l_{2}$

2.5 0 0

2.5 - P P P

$P_{T o t a l} = 2.5 - P + P + P + P_{A r} = 6$

P = 1.5 atm

$K_{P} = \frac{1.5 * 1.5}{1} = 2.25$

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3 months ago

Chemistry Chemistry Chemical Bonding and Molecular Structure

Consider the species CH₄, $N H_{4}^{+} a n d B H_{4}^{-} .$ Choose the correct option with respect to the there species

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alok kumar singh

Contributor-Level 10

Species = CH₄ $N H_{4}^{+}$ $B H_{4}^{?}$

Electrons = 10 10

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Chemistry Biomolecules

What is the zwitter ion class 12?

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Swayam Gupta

Contributor-Level 9

A zwitterion is an ion that contains both negative and positive charges. This is a dipolar ion and is considered neutral.

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Chemistry Biomolecules

What is a peptide bond?

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Swayam Gupta

Contributor-Level 9

It is a covalent chemical bond that connects amino acids to form polypeptide chains.

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Chemistry Biomolecules

What is the function of biomolecules?

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Swayam Gupta

Contributor-Level 9

Different functions of biomolecules include storing genetic information (by nucleic acids), providing energy (by carbohydrates), and building and repairing tissue (by proteins).

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Chemistry Structure of Atom

Which of the following is the correct plot for the probability density $ψ^{2} (r)$ as a function of distance 'r' of the electron from the nucleus for 2s orbital?

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alok kumar singh

Contributor-Level 10

For 2S, number of radial moles = $n - l - 1 = 2 - 0 - 1 = 1$ and $Ψ^{2} (r)$ will always be positive

$∴ o p t i o n (B) i s c o r r e c t ?$ it has one radial node and it is positive.

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