Class 11th
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New answer posted
7 months agoContributor-Level 9
lim (x?0) (tan (? /4+x)¹/? = e^ (lim (x?0) (tan (? /4+x)-1)/x)
= e^ (lim (x?0) (2tanx/ (1-tanx)/x) = e².
New answer posted
7 months agoContributor-Level 9
S? =0 ⇒ (a? +a? ) (11/2)=0 ⇒ a? =-a?
2a? +10d=0 ⇒ a? =-5d.
Sum = a? +a? +.+a? = (a? +a? ) (12/2) = 6 (2a? +22d)
= 6 (2a? +22 (-a? /5) = 6 (2a? -22a? /5) = 6 (-12a? /5)=-72a? /5. k=-72/5.
New answer posted
7 months agoContributor-Level 9
f (x)=a (x-3) (x-α)
f (2)=a (2-α)
f (-1)=a (-4) (-1-α)=4a (1+α)
f (-1)+f (2)=0 ⇒ a (2-α+4+4α)=0 ⇒ a≠0 ⇒ 5α=-2 ⇒ α=-0.4
α ∈ (-1,0)
New answer posted
7 months agoContributor-Level 9
λ=- (sin? θ+cos? θ) = - (sin²θ+cos²θ)²-2sin²θcos²θ)
λ = - (1-½sin²2θ) = ½sin²2θ-1
sin²2θ ∈
λ ∈ [-1, -1/2]
New answer posted
7 months agoContributor-Level 10
Toilet cleaner is acidic (HCl). Neutralize with weak base NaHCO?
New answer posted
7 months agoContributor-Level 10
On moving left to right in a period.
Acidic character of oxides is increase.
3rd period element oxides.
New answer posted
7 months agoContributor-Level 10
Li and Mg form nitrides and have bicarbonates that are unstable
New answer posted
7 months agoNew answer posted
7 months agoContributor-Level 9
189000 to 190000
Sol. ΔH = ΔU + Δn? RT
41000 * 5 = ΔU + 5 * 8.314 * 373
205000 = ΔU + 15505.61
ΔU = 189494.39 J = 189494 J
New answer posted
7 months agoContributor-Level 10
For n=4, l can be 0,1,2,3. m=-2 is possible for l=2,3. So 2 subshells (4d, 4f).
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