Class 11th
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New answer posted
7 months agoContributor-Level 10
The value of (1+sin (2π/9)+icos (2π/9)/ (1+sin (2π/9)-icos (2π/9)³
= (1+cos (5π/18)+isin (5π/18)/ (1+cos (5π/18)-isin (5π/18)³
= (2cos² (5π/36)+2isin (5π/36)cos (5π/36)/ (2cos² (5π/36)-2isin (5π/36)cos (5π/36)³
= (cos (5π/36)+isin (5π/36)/ (cos (5π/36)-isin (5π/36)³
= (e^ (i5π/36)/e^ (-i5π/36)³ = (e^ (i5π/18)³ = e^ (i5π/6) = cos (5π/6)+isin (5π/6)
= -√3/2 + i/2
New answer posted
7 months agoContributor-Level 10
Let L be the common normal to parabola
y = x²+7x+2 and line y = 3x-3
⇒ slope of tangent of y=x²+7x+2 at P=3
⇒ dy/dx|for p = 3
⇒ 2x+7=3 ⇒ x=-2 ⇒ y=-8
So P (-2, -8)
Normal at P: x+3y+C=0
⇒ C=26 (satisfies the line)
Normal: x+3y+26=0
New answer posted
7 months agoContributor-Level 9
In presence of sunlight CFC's molecule divides & release chlorine free radical, which react with ozone give chlorine monoxide radical (CIO°) and oxygen.
CF? Cl? (g) → C (g) + C? Cl (g)
Cl° (g) + O? (g) → ClO° (g) + O? (g)
ClO° (g) + O (g) → Cl° (g) + O? (g)
New answer posted
7 months agoContributor-Level 10
Sol. Let t? denotes r+1th term of (αx? + βx? )¹?
t? = ¹? C? (αx? )¹? (βx? )? = ¹? C? α¹? β? x? ¹?
If t? is independent of x
90-15r=0 ⇒ r=6
This differs from the solution.
Let's follow the solution's powers.
(10-r)/9 - r/6 = 0 ⇒ r=4
maximum value of t? is 10K (given)
⇒ ¹? C? α? β? is maximum
By AM ≥ GM (for positive numbers)
(α³/2+α³/2+β²/2+β²/2)/4 ≥ (α? β? /16)¹/?
⇒ α? β? ≤ 16
So, 10K = ¹? C?16
⇒ K=336
New question posted
7 months agoNew question posted
7 months agoNew question posted
7 months agoNew answer posted
7 months agoContributor-Level 10
i of CaCl? =3. Molality eff=0.15. Molality eff of complex=0.3. [Cr (NH? )? Cl]Cl?
New answer posted
7 months agoContributor-Level 9
Mole of Bromine = 0.08/80 = 10? ³ mole
Molar mass of compound = 0.172/M = 10? ³
M = 0.172/10? ³ = 172g
Molar mass of
New answer posted
7 months agoContributor-Level 10
n (KClO? )=10/122. No. of F = (10/122)*6. No. of F supplied= (100/122). t=11hrs.
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