Class 11th
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New answer posted
a year agoContributor-Level 10
For n=4, l can be 0,1,2,3. m=-2 is possible for l=2,3. So 2 subshells (4d, 4f).
New answer posted
a year ago
Contributor-Level 9
1, 2 and 3 are according to quantum theory but (4) is statement of kinetic theory of gases
New question posted
a year ago
New answer posted
a year agoContributor-Level 10
. τ? about B is zero at equilibrium
T?100 - mg*50 – 2mg*25 = 0
T?100 = 100mg
T? = 1mg
New answer posted
a year agoContributor-Level 10
V? = 36 km/hr = 10 m/s
V? = -72 km/hr = -20 m/s
V? = -1.8 km/hr = -0.5 m/s
V? = V? + V?
= V? + V? - V?
= -0.5 + 10 – (-20)
= -0.5 + 30 = 29.5 m/s
New answer posted
a year agoContributor-Level 10
Let AC = l, BC = 2l, AB = 3l
Apply work-Energy theorem
W? + W? = ΔKE
Mg (3l)sinθ - µmgcosθ (l) = 0+0
µmgcosθl = 3mglsinθ
µ=3tanθ = ktanθ
∴ k=3
New answer posted
a year agoContributor-Level 10
Y ∝ F? V? A? Y = (E/A)/L²
ML? ¹T? ² ∝ (M¹L¹T? ²)? (L¹T? ¹)? (L²)?
a=1, a+b+2c=-1, -2a-b=-2
a=1, b=0, c=-1
Y = F¹V? A? ¹
New answer posted
a year agoContributor-Level 10
T? V? ¹ = T? V? ¹
T? = T? (V? /V? )? ¹ = T? (10)? /? ¹ = T? (10)²/?
ΔV = 5/2 nR; 5/2 * 5 * 3102/5-1
625/6 * 1.5 * 293 = 461440 ≈ 46ks
New answer posted
a year agoContributor-Level 10
From momentum conservation
mui + 0 = mvj + 3mv'
v' = u/3 I - v/3 j
From kinetic energy conservation 1/2 mu² = 1/2 mv² + 1/2 (3m) (u/3)²+ (v/3)²)
Solving, v = u/√2
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