Class 11th
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New answer posted
2 months agoContributor-Level 10
T? V? ¹ = T? V? ¹
T? = T? (V? /V? )? ¹ = T? (10)? /? ¹ = T? (10)²/?
ΔV = 5/2 nR; 5/2 * 5 * 3102/5-1
625/6 * 1.5 * 293 = 461440 ≈ 46ks
New answer posted
2 months agoContributor-Level 10
From momentum conservation
mui + 0 = mvj + 3mv'
v' = u/3 I - v/3 j
From kinetic energy conservation 1/2 mu² = 1/2 mv² + 1/2 (3m) (u/3)²+ (v/3)²)
Solving, v = u/√2
New answer posted
2 months agoContributor-Level 10
ρdrω²r = ρgdh
ω²∫? rdr = g∫? dh
ω²R²/2 = gh
h = ω²R²/2g = 25ω²/2g
New answer posted
2 months agoContributor-Level 10
mω²acosθ = mgsinθ
ω = √ (gtanθ/a)
y = 4cx²
tanθ = dy/dx = 8xC
(tanθ)? , b = 8aC
ω = √ (g*8aC/a) = 2√ (2gC)
New answer posted
2 months agoContributor-Level 10
- Let t? denotes r+1th term of (? x? +? x? )¹?
t? = ¹? C? (? x? )¹? (? x? )? = ¹? C? ¹? x? ¹?
If t? is independent of x
90-15r=0? r=6
This differs from the solution.
Let's follow the solution's powers.
(10-r)/9 - r/6 = 0? r=4
maximum value of t? is 10K (given)
? ¹? C? is maximum
By AM? GM (for positive numbers)
(? ³/2+? ³/2+? ²/2+? ²/2)/4? (? /16)¹/?
? ? ? 16
So, 10K = ¹? C?16
? K=336
New answer posted
2 months agoContributor-Level 10
Circle x²+y²-2x-4y+4=0
⇒ (x-1)²+ (y-2)²=1
Centre: (1,2) radius=1
line 3x+4y-k=0 intersects the circle at two distinct points.
⇒ distance of centre from the line < radius
⇒ |3*1+4*2-k|/√ (3²+4²) < 1
⇒ |11-k|<5
⇒ 6
Number of K is 9.
New answer posted
2 months agoContributor-Level 10
M = ∫ ρdV
M = ∫? (k/r) 4πr²dr
M = 4πkR?²/2 = 2πkR?²
F? = GMm/R?² = 2ω?²R
New answer posted
2 months agoContributor-Level 10
lim (x→1) (x+x²+.+x? -n)/ (x-1) = 820
⇒ lim (x→1) (x-1)/ (x-1)+ (x²-1)/ (x-1)+.+ (x? -1)/ (x-1) = 820
⇒ 1+2+.+n = 820
⇒ n (n+1)=2*820
⇒ n (n+1)=40*41
Since n∈N, so n=40
New answer posted
2 months agoContributor-Level 10
FR > mgcosθR
F > mgcosθ
F > mg √ (R²- (R-a)²)/R ⇒ Mg√ (1- (R-a)²/R²)
New answer posted
2 months agoContributor-Level 10
MOTHER
1? E
2? H
3? M
4? O
5? R
6? T
So position of word MOTHER in dictionary
2*5!+2*4!+3*3!+2!+1
=240+48+18+2+1
=309
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