Class 11th

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3 months ago

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alok kumar singh

Contributor-Level 10

B (OH)3 is orthoboric acid having acidic nature, while Al (OH)3 has amphoteric nature that is acidic and as well as basic

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

B (OH)3 is orthoboric acid having acidic nature, while Al (OH)3 has amphoteric nature that is acidic and as well as basic

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Nowdays liquid CO2 used as washing clothes, because Cl2 and C2H2Cl4 are toxic

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3 months ago

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A
alok kumar singh

Contributor-Level 10

An alkali metal oxide of formula MO2 is super oxide which is formed by K and Rb. KO2 has pale yellow colour and paramagnetic nature, while alkaline earth metal oxides formula MO2 are peroxide and diamagnetic nature.

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3 months ago

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alok kumar singh

Contributor-Level 10

Only (A) and (B) structures have resonance effect. In (A) benzyllic resonance and in (B) allylic resonance of carbocation.

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3 months ago

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alok kumar singh

Contributor-Level 10

Following are the dihedral angles of H2O2 in gas phase and solid (Reverse with respect to question).

Change of angle is the changing of intermolecular interaction in different phase

 

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3 months ago

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V
Vishal Baghel

Contributor-Level 10

Given electronic configuration is for Ga and in 5th period diagonally situated element is Sn with respect to Ga. Hence electronic configuration of Sn is [Kr]4d105s25p2.

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3 months ago

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alok kumar singh

Contributor-Level 10

W1 = 1000 N ->Weight of person at surface of earth W2 = 400 N Þ Weight of person at surface of Mars. There will be a neutral point -N where weight will be zero because at this point net gravitational field due to earth and mars is zero.

 

New answer posted

3 months ago

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alok kumar singh

Contributor-Level 10

70 g – N = 70 a = 70 * 0.2 = 14

->N = 700 – 14 = 686 N

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

For ascent

t a = 2 l a a s c e n t = 2 l g ( s i n θ + μ c o s θ )

For descent

t d = 2 l a d e s c e n t = 2 l g ( s i n θ μ c o s θ )

According question, we can write

μ = 3 5 t a n θ = 3 5 t a n 3 0 ° = 3 5

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