Class 11th

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New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

6 3 = 2 t t = 1

 ->R (-1,0)

    P R 2 + R Q 2 = 2 0 + 5 = 2 5          

 

New answer posted

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Time period of Satellite = T = 2 π R v = ( 4 π 2 R 3 G M ) 1 2  

T α R 3 2 T 2 T 1 = ( 1 . 0 2 R ) 3 2 R 3 2 = ( 1 . 0 2 ) 3 2 = ( 1 + 0 . 0 2 ) 3 2     

The percentage difference in the time periods of the two satellites = Δ T T 1 * 100

= (0.03) * 100 = 3%

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

As we know that υ 2 = ω 2 ( A 2 x 2 )  for SHM, so

υ 1 2 = ω 2 ( A 2 x 1 2 ) . . . . . . . ( i ) , a n d υ 2 2 = ω 2 ( A 2 x 2 2 ) . . . . . . . . . ( i i )

Subtracting equation (ii) from equation (i), we have

υ 1 2 υ 2 2 = ω 2 ( x 2 2 x 1 2 ) ω = 2 π T = υ 1 2 υ 2 2 x 2 2 x 1 2 T = 2 π x 2 2 x 1 2 υ 1 2 υ 2 2

New answer posted

5 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  f ( x ) = { 2 x 2 + 3 , 2 < x < 1 x 2 , 1 x < 0 3 2 1 , 0 x < 1 x 2 3 + 1 2 , 1 x < 2

f ( 1 ) = f ( 1 + ) = f ( 1 ) = 1                

f ( 1 + ) = f ( 1 ) = 1 2 2                

Points of discontinuity

x = 0, 1

New answer posted

5 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

According to ideal gas law we know that

PV = nRT

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

According to question, we can write

New answer posted

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Assuming Tension in metal wire suspended from roof varies linearly and 0 and T0 (developed due its own weight) are tensions are ends of wire of length l .  So

T 1 α ( l 1 l ) , a n d T 2 α ( l 2 l )

T 1 T 2 = l 1 l l 2 l l = T 2 l 1 T 1 l 2 T 2 T 1

New answer posted

5 months ago

0 Follower 22 Views

A
alok kumar singh

Contributor-Level 10

ar (ABC) = 4ar (DEF)

= 4 * 1 2 * | 2 ( 2 5 ) + 1 ( 5 3 ) + 7 ( 3 2 ) | = 2 | 6 + 2 + 7 | = 6

 

New question posted

5 months ago

0 Follower 4 Views

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