Class 11th

Get insights from 8k questions on Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 11th

Follow Ask Question
8k

Questions

0

Discussions

38

Active Users

0

Followers

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Use [x + n] = n + [x], where n z  f (x) = [x] – 10 will be minimum for x [ 0 , 1 0 ]  break the limits as G.I.F. is discontinuous at integral points.

0 1 0 f ( x ) d x = 1 0 9 . . . . 1    

= 1 0 . 1 1 2

0 1 0 | f ( x ) | d x = 1 0 + 9 + . . . . + 1

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

t n = 2 ( 2 3 + 4 3 + 6 3 + . . . . + ( 2 n ) 3 ) ( 1 3 2 3 + 3 3 + . . . . . ( 2 n ) 3 ) n ( 4 n + 3 )

2 * 2 3 * ( n * ( n + 1 ) 2 ) 2 ( 2 n * ( 2 n + 1 ) 2 ) 2 n ( 4 n + 3 )

tn = n

n o w n = 1 1 5 T n = 1 5 . 1 6 2

New answer posted

3 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

  x 2 1 0 x + 9 0

  ( x 1 ) ( x 9 ) 0              

A = {1, 2, 3, ……, 9}

for set B,   f ( x ) ( x 3 ) 2 + 1

total number of such function = 2 * 1 * 1 * 1 * 2 * 3 * 4 * 5 * 6 = 2 * 6! = 1440

New answer posted

3 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Following have the sp3d2 hybridisation

 

 

New answer posted

3 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Po2 = PTotal -   P N 2 5 = ( x / 3 2 x / 3 2 + 2 0 0 2 0 ) * 2 5 x = 8 0 g m

= 25 – 20 = 5bar

Po2 =   n O 2 n O 2 + n N e * P T o t a l

5 = ( x / 3 2 x / 3 2 + 2 0 0 2 0 ) * 2 5 x = 8 0 g m
 

New answer posted

3 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

SO3 -> Sp2 Planar

BF3 -> Sp2 Planar

N O 3 -> Sp2 Planar

SF4 -> Sp3d non-planar

H2O2 -> Sp3 Non-planar

PCl3 -> Sp3 Non –planar

[Al (OH)4]- -> Sp3 Non-planar

XeF4 -> Sp3d2 planar

XeO3 -> Sp3 Non-planar

P H 4 -> Sp3 Non-planar

New answer posted

3 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Let x gm is burnt

Moles = x/280

Heat released by x/280 mol = 2.5 * 0.45 kJ

Heat released by 1 mol =  2 . 5 * 0 . 4 5 * 2 8 0 x = k J

Δ H = Δ U + Δ n g R T Δ H = Δ U            

9 = 2 . 5 * 2 8 0 * 0 . 4 5 x            

x = 35 gm

New answer posted

3 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

For real gas under high pressure,

Z = 1 + P b R T b = R T P = 0 . 0 8 3 * 2 9 8 9 9        

= 0.25 * 10-2 L mol-1

New answer posted

3 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

No. of equivalents of H2SO4 = 100 * 0.1 * 2 = 20

No. of equivalents of NaOH = 50 * 0.1 = 5

No. equivalents of H2SO4 left = 20 – 5 = 15

150 * x = 15

x = 1 1 0 = 0 . 1 N = 1 * 1 0 1 N

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.