Class 11th
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New answer posted
7 months agoContributor-Level 10
This is a Assertion Type Questions as classified in NCERT Exemplar
62. Option (i) i.e.,
Both A and R are correct, and R is the correct explanation of A is the answer as when two or more compounds differ in the position of substituent atom or functional group on the carbon skeleton, they are known as position isomers and this phenomenon is termed as position isomerism. Pent-2-ene and pent-l-ene are position isomers because they differ in the position of the double bond.
New answer posted
7 months agoContributor-Level 10
This is a Assertion Type Questions as classified in NCERT Exemplar
61. Option (iv)
i.e., A is not correct, but R is correct is the answer. This is because canonical structures always have more energy than the resonance hybrid. Resonance hybrids are always found to be more stable than any of the canonical structures since the delocalization of electrons lowers the orbitals energy and gives stability.
New answer posted
7 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
BeSO4 and MgSO4 readily soluble in water while CaSO4, SrSO4 and BaSO4 are insoluble The greater hydration enthalpy of Be2+ and Mg2+ ions overcome the lattice enthalpy factor and therefore, their sulfates are soluble.
New answer posted
7 months agoContributor-Level 10
This is a Assertion Type Questions as classified in NCERT Exemplar
60. Option (i)
i.e., Both A and R are correct, and R is the correct explanation of A is the answer. Since the liquids are having sufficient difference in their boiling points. Liquids having different boiling points vaporize at different temperatures. The vapours are cooled, and the liquids so formed are collected separately.
New answer posted
7 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
(i) As the size of the cation increases, the thermal stability of carbonate increases. The more stable will be the oxide of an alkaline earth metal, the less stable will be the carbonate. Hence, beryllium carbonate will be highly unstable because its oxide will be stable.
(ii) Alkali metals and alkaline earth metals form oxides with oxygen and give metal oxides. The oxides are basic in nature. BeO is an exception because BeO is amphoteric.
They also react with water to form sparingly soluble hydroxides. On increasing the size of the cations beryllium oxide and magnesiu
New answer posted
7 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The element from group 2 is beryllium. Be (OH)2 is amphoteric. It reacts with both acids and bases. It reacts with acid to form beryllium chloride and it reacts with base to form beryllate ion which is soluble in sodium hydroxide. The reaction is shown below.
Be (OH)2+2OH−→ [Be (OH)4]2−
Be (OH)2+2HCl→BeCl2+2H2O
Beryllium sulfate are readily soluble in water.
New answer posted
7 months agoContributor-Level 10
This is a Matching Type Questions as classified in NCERT Exemplar
59. (i) → (a); (ii) → (b); (iii) → (b) : (iv) → (c)
New answer posted
7 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
These two elements have similar properties because of their similar atomic and ionic radii.
(i) Both are lighter element and harder than the other metals in their respective groups.
(ii) The halides of both elements, LiCl and MgCl2 are soluble in ethanol.
New answer posted
7 months agoContributor-Level 10
This is a Matching Type Questions as classified in NCERT Exemplar
58. (i) → (a); (ii) → (a); (iii) → (b)
New answer posted
7 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
(i) O22−+ 2H2O → H2O2+2OH−
(ii) 2O2−+2H2O→2OH−+H2O2+O2
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