Class 11th

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5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

A

A compound X, of boron, reacts with NH3 on heating to give another compound Y which is called inorganic benzene.

3H2H6 x  + 6NH→   3 [BH2 (NH3)2]+ [BH4]−                      2 B3N3H6                                 +          &n

...more

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5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

B

The four terminal hydrogen atoms and two boron atoms are all in the same plane.

There are two bridging hydrogen atoms above and below this plane.

The four terminal B-H bonds are regular two-centre-two-electron bonds, whereas the two bridge (B-H-B) bonds are unique and can be described as three-centre-two-electron bonds, as shown in figure:

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

D

In group 13, the standardised trend of decrease of ionization enthalpy is not monitored.

As we move from Boron to Aluminium the atomic size increases and jonjation enthalpy decreases but when we move ahead from Aluminum to Gallium, the screening effect of 3 d electrons comes into play. The poor shielding effect of the electrons lead to the increase in nuclear charge on the valence electrons and results in increase of jopisation enthalpy.

 

Moving from gallium to Indium, due to the shielding effect of 4 d electrons the ionization enthalpy decreases.

The decre

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

C

Me3SiCl is a soleuless liquid That has a major application in the formation of silicones. On its addition in the process, it blocks the end and controls the chain length of the polymer.

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5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

B

In group 14, as we move down from C to Sn, the size increases and electronegativity decreases. This results in the decrease in M-M bond energy. Hence the catenation property decreases.

Bond energy is the amount of energy required to fragment the atoms combined in a molecule are born into separate atoms. Carbon has maximum bond energy as compared to its other group elements. Therefore, shows maximum catenation property.

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

C

Boric acid is Lewis acid, having six electrons in its valence shell. It combines with water, accepts electrons

from OHof water molecule and complete it octet to 8 and releases H+

Reaction: B (OH)3 + OH − H→ [B (OH)4]+ H+

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Let b be the position vector of the centre of mass of a regular n-polygon.

(n-1) equal point masses are placed at (n-1) vertices of the regular n polygon, therefore for its centre of mass

rCM= n - 1 m b + m a n - 1 m + m = 0

(n-1)mb+ma=0

B=- a n - 1

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

A

Number of items/molecules bonded to the central atom is termed as coordination number. In the given MF63−

Coordination number of metal is six and boron can have topmost coordination number of four as it consists of s and p orbital only and lacks d-orbital. Therefore, boron cannot be compared in the form of MF63−.

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5 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

A

The B2O3 reacts with water to form boric acid hence it is an acidic oxide. As we move down the group electronegativity decreases and the tendency to donate electrons increases therefore basic character increases or acidic character decreases. So, from the given options, the most acidic oxide is B2O3.

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5 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Where weight of the door acts along negative y axis

A force can produce torque only along a direction normal to itself as τ = r * F . So when the door is in the xy plane the torque produced by gravity can only along z direction. Never about an axis passing through y direction. Hence the weight will not produce any torque.

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