Class 11th
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New answer posted
6 months agoContributor-Level 10
42.
(i) Given, equation of lines are
15x + 8y- 34 = 0
15x + 8y + 31 = 0
So, c1 = 34 and c2 = 31, A = 15 and B = 8

New answer posted
6 months agoContributor-Level 10
19. Given, R= { (a, b): a, b z and a – b is an integer}
We know that, the difference of two integers is also an integer.
R= { (a, b): a – b z & a, b z}
Domain of R=Z.
Range of R= Z.
New answer posted
6 months agoContributor-Level 10
18. Given, A={x, y, z}so, n(A)=3
B={1,2} so n(B)=2
? n(A * B)=n(A) *n(B)=3 * 2=6
Hence, no. of relation from A to B=Number of subsets of A * B
=26
=64.
New answer posted
6 months agoContributor-Level 10
17. GivenR= { (x, x3) : x is a prime number less than 10}
R = { (x, x3) : x = 2,3,5,7}
= { (2,23), (3,33), (5,53), (7,73)}
= { (2,8), (3,27), (5,125), (7,343)}
New answer posted
6 months agoContributor-Level 10
40.
The given equation of the line is.
12 (x + 6) = 5 (y- 2)
⇒ 12x + 72 = 5y- 9
⇒ 12x- 5y + 72 + 9 = 0
⇒ 12x- 5y + 82 = 0
The perpendicular distance of point (-1, 1) from the line is given by

New answer posted
6 months agoContributor-Level 10
16. Given, R = { (x, x+5): x {0,1,2,3,4,5}
= { (0,0+5), (1,1+5), (2,2+5), (3,3+5), (4,4+5), (5,5+5)}
= { (0,5), (1,6), (2,7), (3,8), (4,9), (5,10)}
So, domain of R= {0,1,2,3,4,5}
range of R= {5,6,7,8,9,10}
New answer posted
6 months agoContributor-Level 10
15. Given, A= {1,2,3,4,6}
R= { (a, b): a, b A, b is exactly divisible by a}
(i) R= { (1,1), (1,2), (1,3), (1,4), (1,6), (2,2), (2,4), (2,6), (3,3), (3,6), (4,4), (6,6)}
(ii) Domain of R= {1,2,3,4,6}
(iii) Range of R= {1,2,3,4,6}
New answer posted
6 months agoContributor-Level 10


As w lies in IVth quadrant
Cos w = cos 45° and sin w = - sin 45°
= cos (360°- 45°) = sin (360°- 45°)
= cos 315° &nbs
New answer posted
6 months agoContributor-Level 10
14. As R is a relation from set P to Q.
(i) R = { (x, y): x – 2 = y ; 5 ≤ x ≤ 7}
(ii) R = { (5,3), (6,4), (7,5)}
Domain of R= {5,6,7}
range of R= {3,4,5}
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