Class 12th
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New answer posted
8 months agoContributor-Level 10
3.1 EMF of the battery, E = 12 V
Internal resistance of the battery, r = 0.4 Ω
Let the maximum current drawn = I
According to OHM's law, E = Ir
So I = = amp = 30 amp
Therefore, the maximum current can be drawn is 30 ampere.
New question posted
8 months agoNew answer posted
8 months agoBeginner-Level 5
students can check the table for the principal values for all ITFs below;
| Function | Principal Value Range (in radians) |
|---|---|
| sin? ¹x | –? /2 to? /2 |
| cos? ¹x | 0 to? |
| tan? ¹x | –? /2 to? /2 |
| cot? ¹x | 0 to? |
| sec? ¹x | 0 to? (except? /2) |
| cosec? ¹x | –? /2 to? /2 (except 0) |
New answer posted
8 months agoBeginner-Level 5
To understand this, Assume you have a bucket that has infinite number of apples and if your mother asks "give me the apple". How will you figure out which one is "The Apple", she is asking for.
Similarly any inversre trigonometric functions behaves like a Many-one Function; which means,
For Example can have many solutions, we need to fix one solutions which can be used as standerd value for the function.
- A standerd value (Angles) of any inverse trigonometric value lies between a fiexed range is known as principal value.
For Ex; The value of will always lie between –? /2 to? /2.
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8 months agoNew question posted
8 months agoNew question posted
8 months agoNew answer posted
8 months agoContributor-Level 10
7.33
Xe and F2 combine under different conditions to produce XeF2, XeF4, XeF6 as follows:
Ratio | Temperature & Pressure Condition | Reaction |
Excess | at {673K,1bar} | Xe (g) + F2 (g) → XeF2 (s) |
1:5 ratio | at {873K,7bar} | Xe (g) + 2F2 (g) → XeF4 (s) |
1:20 ratio | at {573K,60-70bar} | Xe (g) + 3F2 (g) → XeF6 (s) |
New answer posted
8 months agoContributor-Level 10
7.66
4NaCl + MnO2 + 4H2SO4 MnCl2 + 4NaHSO4 + 2H2O + Cl2
Manganese (IV) oxide reacts with sodium chloride and sulfuric acid to produce manganese (II) chloride, chlorine, sodium bisulfate and water.
This reaction takes place at a temperature near 100°C.
Cl2 + NaI 2NaCl + I2
Chlorine reacts with sodium iodide to produce sodium chloride and iodine. Chlorine - diluted solution.
Sodium iodide - cold solution.
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