Class 12th

A current through a wire-depends on time as

i = a₀t + bt²

Where a₀ = 20A/s and b = 8As^-². Find the charge crossed through a section of the wire in 15s.

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Contributor-Level 10

$\frac{d q}{d t} = t = 20 t + 8 t^{2}$

$\Rightarrow \int_{0}^{q} d q = \int_{0}^{15} (20 t + 8 t^{2}) d t$

$\Rightarrow q = 20 * \frac{1 5^{2}}{2} + 8 . \frac{1 5^{3}}{3} = 11250 C$

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9 months ago

Class 12th Maths

∫[logₑ x] dx, x > 0 and [. ] is greatest integer function, is equal to

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Contributor-Level 10

I = ∫? ² [log? x] dx
By using graph
I = ∫? 0 dx + ∫? ² 1 dx
I = 0 + e² - e

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9 months ago

In the given, figure, the energy levels of hydrogen atom have been shown along with some transitions marked A, B, C, D and E. The transitions A, B and C respectively represents:

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Class 12th Physics Electrostatic Potential and Capacitance

Contributor-Level 10

A : Series limit of Lyman series

B : Third line of Balmer series

C : Second line of Paschen series

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9 months ago

Two equal capacitors are first connected in series and then in parallel. The ratio of the equivalent capacities in

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Contributor-Level 10

When connected in series, equivalent capacitance,

$C_{1} = \frac{C * C}{C + C} = \frac{C}{2}$

When connected in parallel, equivalent capacitance

C₂ = C + C = 2C

$\frac{C_{1}}{C_{2}} = \frac{C / 2}{2 C} = \frac{1}{4}$

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9 months ago

A cell E₁ of emf 6V and internal resistance $2 Ω$ is connected with another cell E₂ of emf 4V and internal resistance $8 Ω$ (as shown in the figure). The potential difference across points X and Y is:

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Class 12th Application of Integrals

Contributor-Level 10

$i = \frac{6 - 4}{2 + 8} = 0.2 A$

$V_{x} + 4 + 0.2 * 8 = V_{Y}$

$\Rightarrow V_{Y} - V_{X} = 5.6 V$

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9 months ago

Area of the figure bounded by the curves y = |x − 1| and y = 3 - |x| is

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Contributor-Level 10

y = |x − 1|, y = 3 – |x|

(A graph is shown with vertices A (1, 0), B (2, 1), C (0, 3), D (-1, 2). The lines are y = x - 1, y = 3 - x, y = 3 + x, and y = -x + 1)

AB = √2, BC = 2√2
⇒ Area = 4 sq. units

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9 months ago

Class 12th Maths

Let f(x) be a polynomial function with negative coefficients and f(−x) = f(x) for all x. Then

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Class 12th Maths Continuity and Differentiability

Contributor-Level 10

f' (0) = 0

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9 months ago

Let f be differentiable on R and h(x) = f(x) − (f(x))² + (f(x))³ + 3x + 2 cos x, then

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Contributor-Level 10

h' (x) = f' (x) – 2f (x).f' (x) + 3 (f (x)².f' (x)
= f' (x)/3 (f (x) - 1/3)² + 2/9)
∴ h' (x) ≥ 0 ⇔ f' (x) ≥ 0

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9 months ago

Class 12th Dual Nature of Radiation and Matter

A teacher in his physics laboratory allotted an experiment ot determine the resistance (G) of a galvanometer. Students took the observations for $\frac{1}{3}$ $\frac{}{}$ deflection in the galvanometer. Which of the below is true for measuring value of G?

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Raj Pandey

Contributor-Level 9

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9 months ago

Given below are two statements:

Statements I : Two photons having equal linear momenta having equal waelengths

Statements II : If the wavelength of photon is decreases, then the momentum and energy of a photon will also decrease.

In the light of the above statements, choose the correct answer from the options given below.

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