Class 12th

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New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

P? + 3NaOH + 3H? O → PH? + 3NaH? PO? (A)
Here, NaH? PO? is a reducing agent.
NaH? PO? + AgNO? + H? O → Ag + HNO? + NaH? PO?
Equivalents of NaH? PO? = equivalents of Ag (n-factor of NaH? PO? = 4)
1 mole * 4 = n moles of Ag * 1
So, moles of Ag = 4.

New answer posted

2 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Kt = 2.303 log? (A? /A? )
K * 570 = 2.303 log? (100/32)
K = [2.303 / 570] [log?10² - log?2? ]
K = [2.303 / 570] [2 - 5 * 0.301] = [2.303 / 570] * 0.495 = 0.002 = 2.0 * 10? ³ s? ¹
Ans = 2

New answer posted

2 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Frequency of message signal, f? = (1.57 * 10? ) / (2 * 3.14) = 2.5 * 10? Hz
Bandwidth = 2f? = 5 * 10? Hz = 50MHz

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

An eye with defect of myopia can not see distant objects clearly, while that of astigmatism sees objects non-uniform and distorted.

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

The magnetic field B is calculated as:
B = 2 * (μ? I / 4πr) + (μ? I / 4πr) = (μ? I / 4πr) * (2 + π)

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

The equation representing the photoelectric effect is given as:
(1/2)mv? ² = hf? - φ . (1)

This continues the solution from number 6 on the previous page.
(1/2)mv? ² = hf? - φ . (2)
With the help of equations (1) and (2), we can write:
v? ² - v? ² = (2h/m) (f? - f? )

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

At the point of intersection in an Ellingham diagram? G for two processes becomes equal, so? G for the reduction becomes zero. A sudden increase in the slope indicates a change in the state of the metal oxide, i.e., from solid to liquid or liquid to vapor.

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Given the initial relationships:
X? = ωL and i? = V? / (ωL)
If the angular frequency ω is halved, the inductive reactance X? is halved, while the peak current i? is doubled.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

In the ammonolysis process, bond cleavage is carried out in the presence of NH? When a halide compound is treated with NH? , the halide ion (X? ) is substituted by an amino group (NH? ) in a nucleophilic substitution reaction.

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