Class 12th

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New answer posted

2 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

dy/dx = xy - 1 + x - y = x (y + 1) - (y + 1) = (x - 1) (y + 1)
⇒ ∫ dy / (1 + y) = ∫ (x - 1) dx ⇒ ln (1 + y) = x²/2 - x + C
For y (0) = 0, c = 0. ∴ ln (1 + y) = x²/2 - x
1 + y = e^ (x²/2 - x)
y (1) = e^ (1/2 - 1) - 1 = e^ (-1/2) - 1

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

In external magnetic field, a magnetic force acts on every small part of the loop in direction perpendicular to the wire. Thus, loop assumes a shape (circular) in which it covers maximum area

New answer posted

2 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

E ∝ m ⇒ E / 13.6 = 207 ⇒ E = 207 * 13.6eV = 2815.2eV

New answer posted

2 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

The Balmer series lies in the visible region of the electromagnetic spectrum.

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

From Radioactive Decay Law,
dN/dt = λ? N + λ? N = λ_eff N
⇒ λ_eff = λ? + λ? ⇒ ln (2)/T = ln (2)/T? + ln (2)/T? ⇒ T = (T? ) / (T? + T? )
(where T, T? , and T? are half-lives)

New answer posted

2 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

3CaO + 2Al → 3Ca + Al? O?
ΔH? = ΣΔH? (Products) - ΣΔH? (Reactants)
ΔH? = [ (0) + (-1675) ] - [ (3 * -635) + (0) ]
ΔH? = -1675 - (-1905) = -1675 + 1905 = 230 kJ
Ans = 230

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Direction of E is perpendicular to the direction of propagation and that of B.
E = cB = 3 * 10? * 2 * 10? = 6 V/m

New answer posted

2 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

Cr? O? ²? + Fe²? - (H? )-> Cr³? + Fe³?
(n=6) (n=1)
Meq Cr? O? ²? = Meq Fe²?
20 * 0.03 * 6 = 15 * M * 1
M = (20 * 0.03 * 6) / 15 = 0.24 = 24 * 10? ²
Ans = 24

New answer posted

2 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

In a purely resistive AC circuit, if V = V? sin (ωt), then the current I is:
I = (V? / X? ) * sin (ωt - π/2)

New answer posted

2 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Magnetic field at centre of a solenoid is proportional to the current through it. Current through C will be one-third of the current through A. So
Magnetic field at the centre of C = 3/3 = 1T.

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